Choose the correct response from the following. A. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the left of -1.21 is 0.1131.0.8869-0.1131-0.7 which rounds to 0.77. OB. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the right of -1.21 is 0.1131. 0.8869-0.1131 -0.7 which rounds to 0.77. OC. By a standard normal distribution table, the cumulative probability to the left of -1.21 is 0.7738, which rounds to 0.77. c. The probability that falls within 0.98 standard deviations of the mean is 0.67 (Round to two decimal places as needed.) d. Choose the correct graph from the following. O А. Q in example Get more help. B. Q G O C. Q Glear all Fina
Choose the correct response from the following. A. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the left of -1.21 is 0.1131.0.8869-0.1131-0.7 which rounds to 0.77. OB. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the right of -1.21 is 0.1131. 0.8869-0.1131 -0.7 which rounds to 0.77. OC. By a standard normal distribution table, the cumulative probability to the left of -1.21 is 0.7738, which rounds to 0.77. c. The probability that falls within 0.98 standard deviations of the mean is 0.67 (Round to two decimal places as needed.) d. Choose the correct graph from the following. O А. Q in example Get more help. B. Q G O C. Q Glear all Fina
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
![Choose the correct response from the following.
A. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the left of -1.21 is 0.1131. 0.8869-0.1131=0.7738,
which rounds to 0.77.
OB. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the right of -1.21 is 0.1131. 0.8869-0.1131=0.7738,
which rounds to 0.77.
OC. By a standard normal distribution table, the cumulative probability to the left of -1.21 is 0.7738, which rounds to 0.77.
c. The probability that falls within 0.98 standard deviations of the mean is 0.67.
(Round to two decimal places as needed.)
d. Choose the correct graph from the following.
A.
Q
an example
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Get more help.
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diave probability is 0.9652, which rounds to 0.97.
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Final check](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7617e6a3-d280-4f44-97ed-ed73937ef3e9%2Fc478174d-5cb4-48a0-8318-a468ff5cfc17%2Fyjmvgbk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Choose the correct response from the following.
A. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the left of -1.21 is 0.1131. 0.8869-0.1131=0.7738,
which rounds to 0.77.
OB. By a standard normal distribution table, the cumulative probability to the left of 1.21 is 0.8869. The cumulative probability to the right of -1.21 is 0.1131. 0.8869-0.1131=0.7738,
which rounds to 0.77.
OC. By a standard normal distribution table, the cumulative probability to the left of -1.21 is 0.7738, which rounds to 0.77.
c. The probability that falls within 0.98 standard deviations of the mean is 0.67.
(Round to two decimal places as needed.)
d. Choose the correct graph from the following.
A.
Q
an example
X
3
Get more help.
20
D
C
44
R
F
5
V
4
T
G
diave probability is 0.9652, which rounds to 0.97.
6
OB.
B
H
&
U
N
8
1
M
9
K
O C.
O
98
P
Command
Q
G
Clear all
option
Final check
Expert Solution
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Step 1: Given Information:
The probability that falls within 0.98 standard deviations of the mean is 0.67.
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