Choose the correct answer for the following. The inverse of the function f(x) = x + 1 is 1 a) f (x) = x + 2 b) f¹ (x) = 2x-2_c)f-1 (x) = 2x + 2 d) none of them 2 If f (x)=e4ln(x3) ' then f'(x) = a) e4ln(x3) b) 12(lnx)e 41 (x3) c) e4n(x³) d) 12x11 D COSX = a)2cos22x-1 If y= In (x²+1) then the value of dy/dx at the point (1,0) is b) 2cos² + 1 c) 2cos² 2x + 1 d) 2cos²-1 0 b) 1/2 c) 1 d) none of them d sec¹√√x= dx b) 2√√x-1 c) 2x√1-x d) 2x√x-1
Choose the correct answer for the following. The inverse of the function f(x) = x + 1 is 1 a) f (x) = x + 2 b) f¹ (x) = 2x-2_c)f-1 (x) = 2x + 2 d) none of them 2 If f (x)=e4ln(x3) ' then f'(x) = a) e4ln(x3) b) 12(lnx)e 41 (x3) c) e4n(x³) d) 12x11 D COSX = a)2cos22x-1 If y= In (x²+1) then the value of dy/dx at the point (1,0) is b) 2cos² + 1 c) 2cos² 2x + 1 d) 2cos²-1 0 b) 1/2 c) 1 d) none of them d sec¹√√x= dx b) 2√√x-1 c) 2x√1-x d) 2x√x-1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Choose the correct answer for the following.
The inverse of the function f(x) = x + 1 is
1
a) f (x) = x + 2 b) f¹ (x) = 2x-2_c)f-1 (x) = 2x + 2 d) none of them
2
If f (x)=e4ln(x3)
'
then f'(x) =
a) e4ln(x3)
b) 12(lnx)e 41 (x3)
c) e4n(x³)
d) 12x11
D
COSX =
a)2cos22x-1
If y= In (x²+1) then the value of dy/dx at the point (1,0) is
b) 2cos² + 1
c) 2cos² 2x + 1
d) 2cos²-1
0
b) 1/2
c) 1
d) none of them
d sec¹√√x=
dx
b) 2√√x-1
c)
2x√1-x
d) 2x√x-1
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