The function f-1 is an inverse function of ƒ if f(ƒ −¹(x)) = f−¹(f(x)). To verify, consider f(x) = 5x f(f−¹(x)) = f−¹(f(x)) f(F-¹(x)) = f (X + 8) 5 Hence, = 5(x + 8) - = x + 8 - 8 || 8 and f-¹(x): ƒ−¹(f(x)) = f−¹( || f(ƒ −¹(x)) = ƒ −¹(f(x)) 8 (5x – 8) + 8 5 = X + 8 5 - 8)

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Q: Show that f(x) = (3x - 2) / (5x - 3) , is its own inverse ?

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Q: Given the function f(x)= { (1,8), (2,16), (3,24), ( 4,32)}, Find the inverse of f-1(x) = {       }

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A: f(-2) = -4

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A: Given f(x) = -3x+2 -6⇒y = -3x+2-6

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Q: Suppose a one-to-one function has domain [1,00) and range (-2,2). What is the domain of the inverse…

A: see below the explanation and answer

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A: We have to find the inverse of the function g(x).

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Q: Let x + 1 f(x) x + 6 ƒ−¹( − 2) = - =

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Q: Use f (x) = x – 3 and g (x) = to find the - given functions. (2 points each) 1) g • f 2) g • g Find…

A: The given functions are: f(x)=x-3          and          g(x)=xx+3