Choose the best answer below. Consider the following complex ion formation equilibrium and it's equilibrium constant, Kf. Which of the following statements is FALSE? Cu2* (aq) + 4CN" (aq) Û Cu(CN)42 (aq) K = 1.0x1025 O Cu2* is a Lewis acid in the reaction, and CN is a Lewis base Removing some of the Cu2* (e.g., by precipitation) will cause some of the complex ion to dissociate O If enough CN" is added, the equilibrium mixture would contain zero Cu2* The complex ion is a Lewis acid-base adduct Adding more CN" will cause more complex ion to form The equilibrium lies in favor of the complex ion

Chemistry by OpenStax (2015-05-04)
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Chapter15: Equilibria Of Other Reaction Classes
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Problem 79E: In a titration of cyanide ion, 28.72 mL of 0.0100 M AgNO3 is added before precipitation begins. [The...
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Choose the best answer below. Consider the following complex ion formation
equilibrium and it's equilibrium constant, Kf. Which of the following statements is
FALSE?
Cu2* (aq) + 4CN" (aq) Û Cu(CN)4² (aq)
K = 1.0x1025
Cu2* is a Lewis acid in the reaction, and CN' is a Lewis base
Removing some of the Cu2* (e.g., by precipitation) will cause some of the
complex ion to dissociate
O If enough CN is added, the equilibrium mixture would contain zero Cu²+
The complex ion is a Lewis acid-base adduct
Adding more CN" will cause more complex ion to form
) The equilibrium lies in favor of the complex ion
Transcribed Image Text:Choose the best answer below. Consider the following complex ion formation equilibrium and it's equilibrium constant, Kf. Which of the following statements is FALSE? Cu2* (aq) + 4CN" (aq) Û Cu(CN)4² (aq) K = 1.0x1025 Cu2* is a Lewis acid in the reaction, and CN' is a Lewis base Removing some of the Cu2* (e.g., by precipitation) will cause some of the complex ion to dissociate O If enough CN is added, the equilibrium mixture would contain zero Cu²+ The complex ion is a Lewis acid-base adduct Adding more CN" will cause more complex ion to form ) The equilibrium lies in favor of the complex ion
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