Choose the answer that best completes the proof that inf(A)=0 where A = for all nEN n? Firstly, we would show that o is a lower bound for A by noticing that 0s Then. O None of these O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that 1 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows that we can choose EA such that W 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
Choose the answer that best completes the proof that inf(A)=0 where A = for all nEN n? Firstly, we would show that o is a lower bound for A by noticing that 0s Then. O None of these O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that 1 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows that we can choose EA such that W 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Choose the answer that best completes the proof that inf(A)=0 where A =
Firstly, we would show that o is a lower bound for A by noticing that 0s
for all nEN-
n2
Then..
O None of these
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
1
<W. But
1
EA so W isn't a lower bound for A, and therefore O must be the infimum of A.
N?
Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
Since W>0 it follows that we can choose
EA such that "
<w. Then W isn't a lower bound for A, and therefore 0 must be the infimum of A.
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
</w. But then
1
<W and
1
EA so W isn't a lower bound for A, and therefore O must
be the infimum of A.
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