Choose the answer that best completes the proof that inf(A)=0 where A = for all nEN n? Firstly, we would show that o is a lower bound for A by noticing that 0s Then. O None of these O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that 1 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows that we can choose EA such that W 0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Choose the answer that best completes the proof that inf(A)=0 where A =
Firstly, we would show that o is a lower bound for A by noticing that 0s
for all nEN-
n2
Then..
O None of these
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
1
<W. But
1
EA so W isn't a lower bound for A, and therefore O must be the infimum of A.
N?
Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
Since W>0 it follows that we can choose
EA such that "
<w. Then W isn't a lower bound for A, and therefore 0 must be the infimum of A.
O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A:
Since W>0 it follows, from the Archimedean Property, that there exists NEN such that
</w. But then
1
<W and
1
EA so W isn't a lower bound for A, and therefore O must
be the infimum of A.
Transcribed Image Text:Choose the answer that best completes the proof that inf(A)=0 where A = Firstly, we would show that o is a lower bound for A by noticing that 0s for all nEN- n2 Then.. O None of these O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: 1 <W. But 1 EA so W isn't a lower bound for A, and therefore O must be the infimum of A. N? Since W>0 it follows, from the Archimedean Property, that there exists NEN such that O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows that we can choose EA such that " <w. Then W isn't a lower bound for A, and therefore 0 must be the infimum of A. O Then we would let W>0 be arbitrary but fixed and show that W can't be a lower bound for A: Since W>0 it follows, from the Archimedean Property, that there exists NEN such that </w. But then 1 <W and 1 EA so W isn't a lower bound for A, and therefore O must be the infimum of A.
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