Choose h and k such that the system has (a) no solution, (b) a unique solution, and (c) many solutions. x₁ +hx₂ = 3 2x₁ +4x₂ = k a. Select the correct answer below and fill in the answer box(es) to complete your choice. (Type an integer or simplified fraction.) A. The system has no solutions only when h and k

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Section3.1: Matrix Operations
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**Title: Solving Systems of Linear Equations**

**Introduction**

In this exercise, we will analyze the conditions under which a system of linear equations has no solution, a unique solution, or many solutions. Consider the following system of equations:

\[ x_1 + h x_2 = 3 \]
\[ 2x_1 + 4x_2 = k \]

---

**Exercise**

*Choose \( h \) and \( k \) such that the system has (a) no solution, (b) a unique solution, and (c) many solutions.*

**Question:**

a. **Select the correct answer below and fill in the answer box(es) to complete your choice.**
(Type an integer or simplified fraction.)

**Options:**

- **A.** The system has no solutions only when \( h \neq \) [ ] and \( k \neq \) [ ].

- **B.** The system has no solutions only when \( h = \) [ ] and \( k \) is any real number.

- **C.** The system has no solutions only when \( h \neq \) [ ] and \( k = \) [ ].

- **D.** The system has no solutions only when \( h \neq \) [ ] and \( k \) is any real number.

- **E.** The system has no solutions only when \( h \neq \) [ ] and \( h \) is any real number.

- **F.** The system has no solutions only when \( k = \) [ ] and \( h \) is any real number.

- **G.** The system has no solutions only when \( h = \) [ ] and \( k = \) [ ].

- **H.** The system has no solutions only when \( h = \) [ ] and \( k \neq \) [ ].

---
Transcribed Image Text:**Title: Solving Systems of Linear Equations** **Introduction** In this exercise, we will analyze the conditions under which a system of linear equations has no solution, a unique solution, or many solutions. Consider the following system of equations: \[ x_1 + h x_2 = 3 \] \[ 2x_1 + 4x_2 = k \] --- **Exercise** *Choose \( h \) and \( k \) such that the system has (a) no solution, (b) a unique solution, and (c) many solutions.* **Question:** a. **Select the correct answer below and fill in the answer box(es) to complete your choice.** (Type an integer or simplified fraction.) **Options:** - **A.** The system has no solutions only when \( h \neq \) [ ] and \( k \neq \) [ ]. - **B.** The system has no solutions only when \( h = \) [ ] and \( k \) is any real number. - **C.** The system has no solutions only when \( h \neq \) [ ] and \( k = \) [ ]. - **D.** The system has no solutions only when \( h \neq \) [ ] and \( k \) is any real number. - **E.** The system has no solutions only when \( h \neq \) [ ] and \( h \) is any real number. - **F.** The system has no solutions only when \( k = \) [ ] and \( h \) is any real number. - **G.** The system has no solutions only when \( h = \) [ ] and \( k = \) [ ]. - **H.** The system has no solutions only when \( h = \) [ ] and \( k \neq \) [ ]. ---
## Finding the General Solution of a System

### Problem Statement
Find the general solution of the system whose augmented matrix is given below:

\[
\begin{pmatrix}
1 & -2 & 0 & -1 & 0 & -9 \\
0 & 1 & 0 & 0 & -7 & 2 \\
0 & 0 & 0 & 1 & 6 & 7 \\
0 & 0 & 0 & 0 & 0 & 0 \\
\end{pmatrix}
\]

### Solution Choices
Select the correct choice below and, if necessary, fill in the answer boxes to complete your answer.

#### Option A
\[
\begin{cases}
x_1 = \boxed{\phantom{0}} \\
x_2 \text{ is free} \\
x_3 = \boxed{\phantom{0}} \\
x_4 \text{ is free} \\
x_5 \text{ is free}
\end{cases}
\]

#### Option B
\[
\begin{cases}
x_1 = \boxed{\phantom{0}} \\
x_2 = \boxed{\phantom{0}} \\
x_3 \text{ is free} \\
x_4 = \boxed{\phantom{0}} \\
x_5 \text{ is free}
\end{cases}
\]

#### Option C
\[
\begin{cases}
x_1 = \boxed{\phantom{0}} \\
x_2 = \boxed{\phantom{0}} \\
x_3 \text{ is free} \\
x_4 = \boxed{\phantom{0}} \\
x_5 = \boxed{\phantom{0}}
\end{cases}
\]

#### Option D
The system is inconsistent.
Transcribed Image Text:## Finding the General Solution of a System ### Problem Statement Find the general solution of the system whose augmented matrix is given below: \[ \begin{pmatrix} 1 & -2 & 0 & -1 & 0 & -9 \\ 0 & 1 & 0 & 0 & -7 & 2 \\ 0 & 0 & 0 & 1 & 6 & 7 \\ 0 & 0 & 0 & 0 & 0 & 0 \\ \end{pmatrix} \] ### Solution Choices Select the correct choice below and, if necessary, fill in the answer boxes to complete your answer. #### Option A \[ \begin{cases} x_1 = \boxed{\phantom{0}} \\ x_2 \text{ is free} \\ x_3 = \boxed{\phantom{0}} \\ x_4 \text{ is free} \\ x_5 \text{ is free} \end{cases} \] #### Option B \[ \begin{cases} x_1 = \boxed{\phantom{0}} \\ x_2 = \boxed{\phantom{0}} \\ x_3 \text{ is free} \\ x_4 = \boxed{\phantom{0}} \\ x_5 \text{ is free} \end{cases} \] #### Option C \[ \begin{cases} x_1 = \boxed{\phantom{0}} \\ x_2 = \boxed{\phantom{0}} \\ x_3 \text{ is free} \\ x_4 = \boxed{\phantom{0}} \\ x_5 = \boxed{\phantom{0}} \end{cases} \] #### Option D The system is inconsistent.
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