chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described by the chemical equation MnO2 (s) + 4 HCl (aq) -> MnCl2 (aq) + 2 H2O (l) + Cl2 (g) How much MnO2 (s) should be added to excess HCl (aq) to abtain 145 mL Cl2 (g) at 25 degrees celsius and 735 Torr? Mass of MnO2 = ? g
chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described by the chemical equation MnO2 (s) + 4 HCl (aq) -> MnCl2 (aq) + 2 H2O (l) + Cl2 (g) How much MnO2 (s) should be added to excess HCl (aq) to abtain 145 mL Cl2 (g) at 25 degrees celsius and 735 Torr? Mass of MnO2 = ? g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl (aq), as described by the chemical equation
MnO2 (s) + 4 HCl (aq) -> MnCl2 (aq) + 2 H2O (l) + Cl2 (g)
How much MnO2 (s) should be added to excess HCl (aq) to abtain 145 mL Cl2 (g) at 25 degrees celsius and 735 Torr?
Mass of MnO2 = ? g
Expert Solution
Step 1
Given:
Volume = 145 mL = 0.145 L.
Temperature = 25 oC = 298 K
Pressure = 735 torr = 0.9671 atm.
Step 2
Calculation for number of moles:
Step by step
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