Chemistry SChangang Con antratrons of Reactents and podects fhar tte feactio 2 Nocg t02 Lo2Im)No [No21 No1(m Tine (s) O0000 O0100 00100 O009S 000 10 0090 O00g0 O.000 660 OO090 D0 20 0030 o0080 O00 7S 0 00 70 1895 2115 4700 800 00060 0 0D 60 O0040 0L0030 data aboue (alculat Ite average rate e n Concentaton (n) op tte product Ouer Of change te ntterual fom 0 Se conds to 2 85 Seconds Calculat t average m of he preduct, Over tha longer rem 0 Secends to 181S Seconds rate op Changgn in Concanteton mter ual 1s te alerage aseter Change ratu or less han of Change part b tn te auerage fatz ep In Part a? hi heactron nureasng decreasin or
Chemistry SChangang Con antratrons of Reactents and podects fhar tte feactio 2 Nocg t02 Lo2Im)No [No21 No1(m Tine (s) O0000 O0100 00100 O009S 000 10 0090 O00g0 O.000 660 OO090 D0 20 0030 o0080 O00 7S 0 00 70 1895 2115 4700 800 00060 0 0D 60 O0040 0L0030 data aboue (alculat Ite average rate e n Concentaton (n) op tte product Ouer Of change te ntterual fom 0 Se conds to 2 85 Seconds Calculat t average m of he preduct, Over tha longer rem 0 Secends to 181S Seconds rate op Changgn in Concanteton mter ual 1s te alerage aseter Change ratu or less han of Change part b tn te auerage fatz ep In Part a? hi heactron nureasng decreasin or
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Chemistry
SChangang Con antratrons of Reactents and podects
fhar tte feactio 2 Nocg t02
Lo2Im)No
[No21
No1(m
Tine (s)
O0000
O0100
00100
O009S
000 10
0090
O00g0
O.000
660
OO090
D0 20
0030
o0080
O00 7S
0 00 70
1895
2115
4700
800
00060
0 0D 60
O0040
0L0030
data aboue (alculat Ite average rate
e
n Concentaton (n) op
tte product Ouer
Of change
te ntterual fom 0 Se conds to 2 85 Seconds
Calculat t average
m of he preduct, Over tha longer
rem 0 Secends to 181S Seconds
rate op Changgn in Concanteton
mter ual
1s te alerage
aseter
Change
ratu
or less han
of Change
part b
tn
te auerage fatz ep
In Part a?
hi heactron nureasng
decreasin
or
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