**Problem Statement:** Calculate the molarity of a 5.00 L solution containing 5.15 mol HNO₃. Enter your answer in the provided box. [Empty Box] M --- **Explanation:** To find the molarity (M) of a solution, you can use the formula: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] In this problem: - Moles of HNO₃ = 5.15 mol - Volume of solution = 5.00 L Plug these values into the formula: \[ \text{M} = \frac{5.15 \, \text{mol}}{5.00 \, \text{L}} = 1.03 \, \text{M} \] The molarity of the solution is 1.03 M.
**Problem Statement:** Calculate the molarity of a 5.00 L solution containing 5.15 mol HNO₃. Enter your answer in the provided box. [Empty Box] M --- **Explanation:** To find the molarity (M) of a solution, you can use the formula: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] In this problem: - Moles of HNO₃ = 5.15 mol - Volume of solution = 5.00 L Plug these values into the formula: \[ \text{M} = \frac{5.15 \, \text{mol}}{5.00 \, \text{L}} = 1.03 \, \text{M} \] The molarity of the solution is 1.03 M.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
Calculate the molarity of a 5.00 L solution containing 5.15 mol HNO₃. Enter your answer in the provided box.
[Empty Box] M
---
**Explanation:**
To find the molarity (M) of a solution, you can use the formula:
\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]
In this problem:
- Moles of HNO₃ = 5.15 mol
- Volume of solution = 5.00 L
Plug these values into the formula:
\[ \text{M} = \frac{5.15 \, \text{mol}}{5.00 \, \text{L}} = 1.03 \, \text{M} \]
The molarity of the solution is 1.03 M.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F073eb5ef-2617-4d6f-9bce-a81ca84c4945%2Ff1127fd9-be07-4d0c-8588-4b6ceab69d30%2F8ptf8b.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Calculate the molarity of a 5.00 L solution containing 5.15 mol HNO₃. Enter your answer in the provided box.
[Empty Box] M
---
**Explanation:**
To find the molarity (M) of a solution, you can use the formula:
\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]
In this problem:
- Moles of HNO₃ = 5.15 mol
- Volume of solution = 5.00 L
Plug these values into the formula:
\[ \text{M} = \frac{5.15 \, \text{mol}}{5.00 \, \text{L}} = 1.03 \, \text{M} \]
The molarity of the solution is 1.03 M.
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