R Compound X has a molar mass of 102.17 g mol -1 and the following composition: element mass % carbon 58.77% hydrogen 13.81% nitrogen 27.42% Write the molecular formula of X. Continue O20 MacBook Air 08 F3 IS DD F1 F2 F4 F5 $ 4 # V % 2 Q

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Q: How many hydrogen atoms are in 0.1488 g of phosphoric acid, H.PO.?

A: One mole of H3PO4 = 6.022 × 2023 formula…

Q: The percentage of water in F e Cl3 dot 5H2O is: 38.70% 35.7% 37.2 % 38.4 % Question 6

A: Mass percentage is defined as quantity of substance present in 100 g of the compound. It is a method…

Q: Complete the table. Element Moles Mass Cr 0.00442 Fe 73.5 mg Ti 1.009 x 10-3 Hg 1.78 kg

A: Mole is represented by the symbol mol. It is unit of measurement of substance. Mass is defined as…

Q: Determine the number of grams of Q2Z3 in 0.13 mol of Q₂Z3

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Q: made-up compound: J2(QZ3)2 Determine the number of molecules of J₂(QZ3)2 in 7.2 grams of J₂(QZ3)2…

A: Given -> Weight of J2(QZ3)2 = 7.2 gram  Atomic mass of J = 19.00 g/mole Atomic mass of Q = 35.00…

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Q: Which oof the following sample contains the fewest number of hydrogen atoms? 2.0 mol H2O 1.5 mol…

A: Mole relation gives relationship between number of moles and number of atoms  1 mol = 6.022 × 1023…

Q: Write the molecular formula of X? .

A: This is a emperical formula and molecular formula determination type  problem. Details calculation…

Q: What is the percent by mass of carbon in ethylamine, C2H7N? Note the following atomic weights: H…

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Q: Determine the number of moles in 3.06 x 1023 formula units of CaCl₂.

A: From the knowledge of mole concepts, 1 mole of CaCl2 contains 6.023 × 1023 formula units of CaCl2.

Q: A gaseous compound containing carbon and hydrogen was analyzed and found to consist of 83.65% carbon…

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Q: . A 67.0 g sample of a compound was found to contain 40.2 g of carbon, 3.00 g of hydrogen and 23.8 g…

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Q: Calculate the moles of Cl in 25.0 g of XYCl3 if the compound XYCl3 has a molar mass of 119.38 g/mol.

A: The above given molecule is a chlorine containing compound. As per the given formula the given…

Q: Percent Element Atomic Mass Composition 35.95% 12.011 amu H 1.69% 1.008 amu N 10.49% 14.007 amu Na…

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Q: Determine the number of moles of cesium in 50.0 g of cesium.

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Q: (2) How many molecules are in 30.1 g of sulfur dioxide? a. 1.81 x 1025 b. 2.83 x 1023 c. 6.02 x 1023…

A: Given , (a) Sulphur Dioxide (b) Ammonia

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Q: Which is the molecular formula of a sample of a compound containing 6.444 g of boron (B) and 1.803 g…

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Q: A compound was analyzed and found to contain 52.17% C, 13.13% H and 34.78% O. What is the empirical…

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Q: Compound X has a molar mass of 104.01 g mol and the following composition: element nitrogen fluorine…

A: Molar mass = 104.01 g/mol Molecular Formula of X = ?

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A: Molecular formula can be calculculated by using below formula : Molar massg/molEmpirical formula…

Q: How many hydrogen atoms are in 5.0 g of citric acid (CóHg87)? O 1.6 x 10²² Hydrogen atoms O 4.6 ×…

A: Mass of Citric Acid = 5.0 gMolar mass of Citric Acid = 192.124 g/moleMoles of Citric Acid = Mass of…

Q: How many atoms of sulfur are in a 2.500 mole sample of pure sulfur? * 1.505 x 1024 5.69 x 10-24 110.…

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Q: :12hcyA/viewt What is the mass of 1.34x10^25molecules of Magnesium? * O 204g O 541g O 72,900g O…

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Q: The molecule CH2CHCH3CH2CHF(CH3)2CCH3 contains H atoms 1. 16 2. 22 3. 18 4. 20

A: The given compound is CH2CHCH3CH2CHF(CH3)2CCH3  we need to calculate total number of hydrogens

Q: Determination of Hydrate Formula: barium chloride hydrate  Data:…

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Q: How many moles of atoms are in 5.00 g of ¹3C?

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Q: What is the percent mass of carbon in H2C2O4? O 26.68% O 71.08% O 2.24% O 13.3%

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Q: The molar mass and empirical formula of several compounds listed. Find the molecular formula of…

A: Empirical formula refers to the formula of a compound in which the elements are present in the…

Q: What is the empirical formula of a compound with a molecular formula of CH₁0N₂O4? C C₂H₂N₂O₂…

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.