**Question 7 of 32** **Question:** What quantity in moles of iron atoms do you have if you have \(2.50 \times 10^{23}\) atoms of iron? (The mass of one mole of iron is 55.85 g.) **Answer Field:** 20 mol **Input Interface:** A numeric keypad with buttons labeled 1 through 9, 0, and additional buttons for a decimal point (.), a plus/minus sign (+/-), a backspace (X), a clear button (C), and an exponent notation button (x 10^). **Explanation:** In this question, the goal is to determine the number of moles of iron atoms from a given number of atoms. To calculate this, you can use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole). The formula is: \[ \text{Moles of iron atoms} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \] This page on an educational website presents learners with the question and a user-friendly interface to input their answers using the keypad.
**Question 7 of 32** **Question:** What quantity in moles of iron atoms do you have if you have \(2.50 \times 10^{23}\) atoms of iron? (The mass of one mole of iron is 55.85 g.) **Answer Field:** 20 mol **Input Interface:** A numeric keypad with buttons labeled 1 through 9, 0, and additional buttons for a decimal point (.), a plus/minus sign (+/-), a backspace (X), a clear button (C), and an exponent notation button (x 10^). **Explanation:** In this question, the goal is to determine the number of moles of iron atoms from a given number of atoms. To calculate this, you can use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole). The formula is: \[ \text{Moles of iron atoms} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \] This page on an educational website presents learners with the question and a user-friendly interface to input their answers using the keypad.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 7 of 32**
**Question:**
What quantity in moles of iron atoms do you have if you have \(2.50 \times 10^{23}\) atoms of iron? (The mass of one mole of iron is 55.85 g.)
**Answer Field:**
20 mol
**Input Interface:**
A numeric keypad with buttons labeled 1 through 9, 0, and additional buttons for a decimal point (.), a plus/minus sign (+/-), a backspace (X), a clear button (C), and an exponent notation button (x 10^).
**Explanation:**
In this question, the goal is to determine the number of moles of iron atoms from a given number of atoms. To calculate this, you can use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole).
The formula is:
\[ \text{Moles of iron atoms} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \]
This page on an educational website presents learners with the question and a user-friendly interface to input their answers using the keypad.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffadaae1f-222d-4466-9524-324e8985bba5%2Fe366b909-f436-498b-92f6-496e475dcc6e%2Fmkm8cq8.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 7 of 32**
**Question:**
What quantity in moles of iron atoms do you have if you have \(2.50 \times 10^{23}\) atoms of iron? (The mass of one mole of iron is 55.85 g.)
**Answer Field:**
20 mol
**Input Interface:**
A numeric keypad with buttons labeled 1 through 9, 0, and additional buttons for a decimal point (.), a plus/minus sign (+/-), a backspace (X), a clear button (C), and an exponent notation button (x 10^).
**Explanation:**
In this question, the goal is to determine the number of moles of iron atoms from a given number of atoms. To calculate this, you can use Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole).
The formula is:
\[ \text{Moles of iron atoms} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \]
This page on an educational website presents learners with the question and a user-friendly interface to input their answers using the keypad.
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