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Question 5 A drug has benzene ring with multiple substituents, predict the sign of Hammett Substitution Constant () of (OH), (OH), and (NO2). OH HO HO Drug o_m(OH) is negative, o_p(OH) is negative, o_m(N02) is positive O o_m(OH) is positive, o_p(OH) is positive, o_m(NO2) is negative Oo_m(OH) is positive, a_p(OH) is negative, o_m(NO2) is positive Oo_m(OH) is negative, o p(OH) is negative, o_m(NO2) is negative O All the options are wrong.

Question 5 A drug has benzene ring with multiple substituents, predict the sign of Hammett Substitution Constant () of (OH), (OH), and (NO2). OH HO HO Drug o_m(OH) is negative, o_p(OH) is negative, o_m(N02) is positive O o_m(OH) is positive, o_p(OH) is positive, o_m(NO2) is negative Oo_m(OH) is positive, a_p(OH) is negative, o_m(NO2) is positive Oo_m(OH) is negative, o p(OH) is negative, o_m(NO2) is negative O All the options are wrong.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 5 A drug has benzene ring with multiple substituents, predict the sign of Hammett Substitution Constant () of (OH), (OH), and (NO2). OH HO HO Drug o_m(OH) is negative, o_p(OH) is negative, o_m(N02) is positive O o_m(OH) is positive, o_p(OH) is positive, o_m(NO2) is negative Oo_m(OH) is positive, a_p(OH) is negative, o_m(NO2) is positive Oo_m(OH) is negative, o p(OH) is negative, o_m(NO2) is negative O All the options are wrong.
Transcribed Image Text:Question 5 A drug has benzene ring with multiple substituents, predict the sign of Hammett Substitution Constant () of (OH), (OH), and (NO2). OH HO HO Drug o_m(OH) is negative, o_p(OH) is negative, o_m(N02) is positive O o_m(OH) is positive, o_p(OH) is positive, o_m(NO2) is negative Oo_m(OH) is positive, a_p(OH) is negative, o_m(NO2) is positive Oo_m(OH) is negative, o p(OH) is negative, o_m(NO2) is negative O All the options are wrong.
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