Hello I need help with this problem. I tried solving it, but i couldnt figure it out, i provided the correct answers. the problem is that the formula im being asked to use for radius is the one i added below, so i have to get that answer using that, can u plz explain it. thanks much! Nickel has a face-centered cubic unit cell. The density of nickelis 6.84 g/cm³. Calculate a value for the atomic radius of nickel.l = 2.828fcc = y atoms.d=6:8491cm³V=l³rearrange may be?l=218280Find liV = mMatamsNi.E I need to use・this formulafor radius..3,898 x 10-226.8461cm ³1. mul6.022x1023and final answerswere r=136pm·and I = 3.85 x 1.0=8cmfrom the text book..a.toms2gŀ:2.828= -5.83x10-23. 3..cm.58.69 g/mol1.mol3.898gNiX10-22

The question is based on the concept of solid state.We need to calculate radius of nickel atom.

Answered: Nickel has a face-centered cubic unit…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Hello I need help with this problem. I tried solving it, but i couldnt figure it out, i provided the correct answers. the problem is that the formula im being asked to use for radius is the one i added below, so i have to get that answer using that, can u plz explain it. thanks much!

Nickel has a face-centered cubic unit cell. The density of nickel
is 6.84 g/cm³. Calculate a value for the atomic radius of nickel.
l = 2.828
fcc = y atoms.
d=6:8491cm³
V=l³
rearrange may be?
l=218280
Find li
V = m
Matams
Ni.
E I need to use
・this formula
for radius..
3,898 x 10-22
6.8461cm ³
1. mul
6.022x1023
and final answers
were r=136pm
·and I = 3.85 x 1.0=8cm
from the text book.
.a.toms
2g
ŀ:
2.828
= -5.83x10-23. 3.
.cm.
58.69 g/mol
1.mol
3.898
g
Ni
X10-22

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