this is homework [References]A salt whose molar mass is 145.43 g/mol is used to make an aqueous solution that is 45.4 % by mass.How many moles of the salt are present?molmolHow many moles of water are present?What is the mole fraction of the salt in the solution?Try Another Version1 item attempt remainingSubmit Answer

Answered: [References] A salt whose molar mass is…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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[References]
A salt whose molar mass is 145.43 g/mol is used to make an aqueous solution that is 45.4 % by mass.
How many moles of the salt are present?
mol
mol
How many moles of water are present?
What is the mole fraction of the salt in the solution?
Try Another Version
1 item attempt remaining
Submit Answer

Expert Solution

Step 1

Given in question that , molar mass of solute is 145.43 g/mol. Also given that mass percentage of solution is 45.4% , it means that if solution has 100 g of total weight the mass of solute is 45.4 g and solvent , water has mass of (100-45.4) = 54.6 g.

Moles of any component can be calculated by using following formula -

Moles = mass /molar mass

While mole fraction of any component can be calculated by using Following formula -

Mole fraction of the component = moles of that component/ total number of moles of all components present in solution

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