The data given in the table below is for the following reaction (run at 25°C): 2 NO+ O → 2 NO, Initial Concentration (M) Experiment Initial rate NO Mol/(L - s) 1 0.0010 0.0010 7 x 10 2. 0.0010 0.0020 14 x 10 3. 0.0010 0.0030 21 x 10+ 4. 0.0020 0.0030 84 x 10* 0.0030 0.0030 189 x 10 1. Determine the orders of the reaction with respect to NO and O, (show all work): (2-2) 14810-Ms [00010] Lo.002] IK [0.0010]"[0.001o NO 2 od ocder 2= (2)°=70-1 (3-4) 84x6-6 Mi- klo002a". [o.0030] k [a001o". [a0080] 40(2)2m-2 02= 44 order 71

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