Benzoic acid, 1.68 g, is reacted with oxygen in a constant volume calorimeter to form H₂O(l) and CO2(g) at 298K. The mass of the water in the inner bath is 1.120E3 g. The temperature of the calorimeter and its contents rises 4.35 K as a result of this reaction. Calculate the calorimeter constant. For the reaction C6H5COOH(s) + 15/2 O2(g) → 7CO2(g) + 3H2O(l), AHOR=-3227kJ mol-1 Physical constants: R= 8.3145 J mol-1 K-1 Heat capacity of water: CH20,m = 75.3 J mol-1 K-1 Ccalorimeter = JK-1

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.76QP: A sample of benzene, C6H6, weighing 3.51 g was burned in an excess of oxygen in a bomb calorimeter....
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Benzoic acid, 1.68 g, is reacted with oxygen in a constant volume calorimeter to form H₂O(l) and
CO2(g) at 298K. The mass of the water in the inner bath is 1.120E3 g. The temperature of the
calorimeter and its contents rises 4.35 K as a result of this reaction. Calculate the calorimeter constant.
For the reaction C6H5COOH(s) + 15/2 O2(g) → 7CO2(g) + 3H2O(l), AHOR=-3227kJ mol-1
Physical constants:
R= 8.3145 J mol-1 K-1
Heat capacity of water: CH20,m = 75.3 J mol-1 K-1
Ccalorimeter =
JK-1
Transcribed Image Text:Benzoic acid, 1.68 g, is reacted with oxygen in a constant volume calorimeter to form H₂O(l) and CO2(g) at 298K. The mass of the water in the inner bath is 1.120E3 g. The temperature of the calorimeter and its contents rises 4.35 K as a result of this reaction. Calculate the calorimeter constant. For the reaction C6H5COOH(s) + 15/2 O2(g) → 7CO2(g) + 3H2O(l), AHOR=-3227kJ mol-1 Physical constants: R= 8.3145 J mol-1 K-1 Heat capacity of water: CH20,m = 75.3 J mol-1 K-1 Ccalorimeter = JK-1
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