Chemistry: Form N6.4.1A Using the Combined Gas PHASES OF MATTER Page 5. Initial-1 Final-2 Volume Pressure Temperature Ti Volume Pressure Temperature VI P1 V2 P2 26.5°C 2°C K=°C+273 K=? 16.5L 107.3kPa? K=°C+273 18.0mL 104.4kPa K= ?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use the combined gas law by plugging in the numbers into it and solve the missing part
Chemistry: Form N6.4.1A
Using the Combined Gas La
PHASES OF MATTER
Page
5.
Initial-1
Final-2
Volume
Pressure
Temperature
Volume
Pressure
Temperature
VI
P1
V2
P2
26.5°C
2°C
16.5L
107.3kPa?
K=°C+273
18.0mL
104.4kPa
K=°C+273
K= ?
K=?
Acti
Go to
Transcribed Image Text:Chemistry: Form N6.4.1A Using the Combined Gas La PHASES OF MATTER Page 5. Initial-1 Final-2 Volume Pressure Temperature Volume Pressure Temperature VI P1 V2 P2 26.5°C 2°C 16.5L 107.3kPa? K=°C+273 18.0mL 104.4kPa K=°C+273 K= ? K=? Acti Go to
6.
Final-2
Initial-1
Pressure
P2
Pressure
Temperature
T2
Volume
Temperature
Volume
VI
P1
ST °C
K-°C+273
K=?
?°C
2.0L
95.3kPa
K=°C+273
2.25mL
SP
K= ?
SP = Standard Pressure (101.3 kPa or 1.0 atm)
ST = Standard Temperature (0°C or 273 K)
Act
Transcribed Image Text:6. Final-2 Initial-1 Pressure P2 Pressure Temperature T2 Volume Temperature Volume VI P1 ST °C K-°C+273 K=? ?°C 2.0L 95.3kPa K=°C+273 2.25mL SP K= ? SP = Standard Pressure (101.3 kPa or 1.0 atm) ST = Standard Temperature (0°C or 273 K) Act
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