A sample of neon gas at a pressure of 1.19 atm and a temperature of 267 °C, occupies a volume of 478 mL. If the gas is cooled at constant pressure until its volume is 360 mL, the temperature of the gas sample will be °C. rogress

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

A sample of **neon** gas at a pressure of **1.19 atm** and a temperature of **267 °C**, occupies a volume of **478 mL**. If the gas is **cooled** at constant pressure until its volume is **360 mL**, the temperature of the gas sample will be _____ °C.

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**Attempts Remaining:** 9 more group attempts remaining

**Explanation:**

This question involves using the principles of gas laws, particularly Charles's Law which states that at constant pressure, the volume of a given mass of gas is directly proportional to its temperature (in Kelvin). The relation is given by:

\[ \frac{V1}{T1} = \frac{V2}{T2} \]

Where:
- \( V1 \) and \( V2 \) are the initial and final volumes, respectively.
- \( T1 \) and \( T2 \) are the initial and final temperatures, respectively.

To find the final temperature (\( T2 \)), rearrange the equation to:

\[ T2 = T1 \times \frac{V2}{V1} \]

Remember to convert temperatures to Kelvin by adding 273.15.
Transcribed Image Text:**Question:** A sample of **neon** gas at a pressure of **1.19 atm** and a temperature of **267 °C**, occupies a volume of **478 mL**. If the gas is **cooled** at constant pressure until its volume is **360 mL**, the temperature of the gas sample will be _____ °C. **Options for Interaction:** - Submit Answer - Retry Entire Group **Attempts Remaining:** 9 more group attempts remaining **Explanation:** This question involves using the principles of gas laws, particularly Charles's Law which states that at constant pressure, the volume of a given mass of gas is directly proportional to its temperature (in Kelvin). The relation is given by: \[ \frac{V1}{T1} = \frac{V2}{T2} \] Where: - \( V1 \) and \( V2 \) are the initial and final volumes, respectively. - \( T1 \) and \( T2 \) are the initial and final temperatures, respectively. To find the final temperature (\( T2 \)), rearrange the equation to: \[ T2 = T1 \times \frac{V2}{V1} \] Remember to convert temperatures to Kelvin by adding 273.15.
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At constant pressure, volume occupied by a gas is directly proportional to its temperature.

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