Decomposition of H202 Data (1) - WordSearchDesignLayoutReferencesMailingsReviewViewDeveloperHelp12 A A Aa、 |A|三▼三▼i、|EE|2↓TPolalAaBbCcD AABBCCD AaBbC AABBCCC AaI U - ab x, x A A-|■===|=。12-田T No Spac.. Heading 1T NormalHeading 2TitlFontParagraphStylesChemical equation used:2 Mn04 + 5 H2O2 + 6 H* →2 Mn2+ + 5 02 + 8 H2O[MnO4] = 0.0090 MVolume H2O2 used: 1.0 mLVolume H2S04 used: 7.0 mLTrial 1: 41.9 mL MnO4 usedTrial 2: 40.4 mL usedTrial 3: 40.01 mL usedRemember you want to find the M (mol/L) of H2O2. You must use stoichiometry to findmoles of H2O2 and the volume of hydrogen peroxide used to get liters. Calculate theconcentration for each trial and average the results.Thar nocho mictrv

The balanced equation has an equal number of atoms or ions on both sides of the reaction arrow. The…

Chemical equation used: 2 MnO4 + 5 H2O2 + 6 H* 2 Mn2+ + 5 O2 + 8 H2O [MnO4] = 0.0090 M Volume H2O2 used: 1.0 mL Volume H2SO4 used: 7.0 mL Trial 1: 41.9 mL MnO4 used Trial 2: 40.4 mL used Trial 3: 40.01 mL used Remember you want to find the M (mol/L) of H2O2. You must use stoichiometry to find moles of H2O2 and the volume of hydrogen peroxide used to get liters. Calculate the concentration for each trial and average the results.

Chemical equation used: 2 MnO4 + 5 H2O2 + 6 H* 2 Mn2+ + 5 O2 + 8 H2O [MnO4] = 0.0090 M Volume H2O2 used: 1.0 mL Volume H2SO4 used: 7.0 mL Trial 1: 41.9 mL MnO4 used Trial 2: 40.4 mL used Trial 3: 40.01 mL used Remember you want to find the M (mol/L) of H2O2. You must use stoichiometry to find moles of H2O2 and the volume of hydrogen peroxide used to get liters. Calculate the concentration for each trial and average the results.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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