Check the following hypotheses: 1) Verification of hypothesis variances Ho: o2 = 0; H₁: 02/2 # 03 2) Verification of hypothesis variances Ho: o² = 0²; H₁: 0² # 0² 3) Verification of hypothesis variances Ho: o2 = 0; H₁: 0² 0² σ #
Check the following hypotheses: 1) Verification of hypothesis variances Ho: o2 = 0; H₁: 02/2 # 03 2) Verification of hypothesis variances Ho: o² = 0²; H₁: 0² # 0² 3) Verification of hypothesis variances Ho: o2 = 0; H₁: 0² 0² σ #
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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Question
Based on the following values:
Mathematical expectation:
E(X) = ∑Xn1 = 1204 = 30
E(Y) = ∑Yn2 = 1884 = 47
E(Z) = ∑Zn3 = 1784 = 44.5
Variance:
var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26
var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18
var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667
Root mean square deviation
sd(X)= var(X) =26 = 5.0990
sd(Y)= var(Y) =18 = 4.2426
sd(Z)= var(Z) =133.6667 = 11.5614
|
Y |
Z |
|
|
25 |
44 |
28 |
|
28 |
43 |
48 |
|
37 |
49 |
55 |
|
30 |
52 |
47 |
1. Expectation |
120 |
188 |
178 |
2. Variance |
26 |
18 |
133.6667 |
3. root mean square deviation |
5.099 |
4.2426 |
11.5614 |
Check the hypothesis in the images. The table values are in the other image below
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