CH,COOC,H, the rate constant at 675.0 K is 0.00106/s and the rate constant at 719.0 K is 0.00939 /s. +CH;COOH + C,H, The activation energy for the gas phase decomposition of ethyl acetate is | kJ/mol.

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Chapter1: Chemical Foundations
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CH,COOC,H,–CH,COOH + C,H,
the rate constant at 675.0 K is 0.00106 /s and the rate constant at 719.0 K
is 0.00939 /s.
The activation energy for the gas phase decomposition of ethyl acetate
is
kJ/mol.
Arrhenius Equation
The variation of the rate constant with temperature can be expressed by
the Arrhenius Equation. The two-point form of this equation can be written
as:
"(수)- (뉴
Ea
In
T1
where k and kj are the values of the rate constant at the Kelvin
temperatures T2 and T1, respectively, E is the activation energy, and R is
the ideal gas constant.
You may see slightly different, but equivalent, forms of this equation. It's
easy to confuse the different forms. They will all give the same result, but
not if you mix parts of one form with parts of another!
Here are two more forms that you are likely to see. Can you spot the
differences between these and the form above?
Ea
k1
In
ka
ln () --G
k2
Ea
R
T2
In the first one, the k2 and ki terms are interchanged. To balance this, the
1
and
T2
terms are as well.
In the second one, a minus sign precedes
Ea
This is balanced by
1
1
interchanging
and
T
Transcribed Image Text:CH,COOC,H,–CH,COOH + C,H, the rate constant at 675.0 K is 0.00106 /s and the rate constant at 719.0 K is 0.00939 /s. The activation energy for the gas phase decomposition of ethyl acetate is kJ/mol. Arrhenius Equation The variation of the rate constant with temperature can be expressed by the Arrhenius Equation. The two-point form of this equation can be written as: "(수)- (뉴 Ea In T1 where k and kj are the values of the rate constant at the Kelvin temperatures T2 and T1, respectively, E is the activation energy, and R is the ideal gas constant. You may see slightly different, but equivalent, forms of this equation. It's easy to confuse the different forms. They will all give the same result, but not if you mix parts of one form with parts of another! Here are two more forms that you are likely to see. Can you spot the differences between these and the form above? Ea k1 In ka ln () --G k2 Ea R T2 In the first one, the k2 and ki terms are interchanged. To balance this, the 1 and T2 terms are as well. In the second one, a minus sign precedes Ea This is balanced by 1 1 interchanging and T
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