### Problem Statement:Charges \( q_1 \) and \( q_2 \) are placed on the y-axis at \( y = 0 \) and \( y = 25.1 \) m, respectively. If \( q_1 = -46.8 \) pC and \( q_2 = +64 \) pC, determine the net flux through a spherical surface (radius = \( 9.5 \) m) centered on the origin.Round your answer to 2 decimal places.#### Answer:\[ \text{Add your answer} \]### Explanation:Given:- \( q_1 = -46.8 \) pC (placed at \( y = 0 \) m)- \( q_2 = +64 \) pC (placed at \( y = 25.1 \) m)- Radius of the spherical surface \( = 9.5 \) mThe objective is to determine the net electric flux through the spherical surface centered at the origin. The concept of electric flux can be tackled using Gauss's Law, which states:\[ \Phi_E = \frac{q_{\text{enc}}}{\epsilon_0} \]where \( q_{\text{enc}} \) is the enclosed charge within the Gaussian surface and \( \epsilon_0 \) is the permittivity of free space (\( \approx 8.85 \times 10^{-12} \, \text{F/m} \)).The charge \( q_2 \) is located outside the spherical surface (as 25.1 m > 9.5 m), so it does not contribute to the enclosed charge. Therefore, only \( q_1 \) is inside the spherical surface:\[q_{\text{enc}} = q_1 = -46.8 \, \text{pC} = -46.8 \times 10^{-12} \, \text{C}\]Using Gauss's Law to find the net flux \( \Phi_E \):\[\Phi_E = \frac{q_{\text{enc}}}{\epsilon_0} = \frac{-46.8 \times 10^{-12} \, \text{C}}{8.85 \times 10^{-12} \, \text{F/m}}\]Upon calculating:\[\Phi_E \approx -5

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Charges q, and 92 are placed on the y-axis at y = 0 and y = 25.1 m, respectively. If q, = -46.8 pC and q2= +64 pC, determine the net flux through a spherical surface (radius = 9.5 m) centered on the origin. Round your answer to 2 decimal places.