charge of 2 C moves with a velocity V=(2i-4j)m/s in a region in which magnetic field is B=(1i+3j) T. What is the magnetic force this particle experiences ?
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A charge of 2 C moves with a velocity V=(2i-4j)m/s in a region in which magnetic field is B=(1i+3j) T. What is the magnetic force this particle experiences ?
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- When a proton has a velocity of (2i+8j)*10^6 m/s , it experiences a force of -1.6*10^-13k N. . In a second experiment with the same B field, the particle is moving along the + z-axis and under these new conditions it experiences a force along the + x-axis . What is the magnetic field? answer should be in (i,j,k)An electron (with mass mp = 9.1x 10-31 kg, charge ∣∣qe∣∣ = 1.6 x 10-19 C) moving with a speed of 2.50 x 105 m/s, enters the Earth’s magnetic field (B= 55.0 μμT, Northbound). If the electron moves westward, the magnetic force (FB) acting on it should be Group of answer choices 2.2 x 10-18 N eastward 2.2 x 10-18 N downward 7.04 x 10-16 N upward 2.2 x 10-18 N upwardA particle that has an 8.6-μC charge moves with a velocity of magnitude 4.8 × 105 m/s along the +x axis. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.577 N. Find the magnitude of the magnetic field