charge density "2", at a point located on its axis of symmetry perpendicular to the plane of the ring, at a distance "d" from its center is: V = 2π kλR / √d² + R², where "k" is the constant of electrical proportionality.

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89. To show that the electric potential created by a very thin ring of radius "R", uniform linear
charge density "2", at a point located on its axis of symmetry perpendicular to the plane of the
ring, at a distance "d" from its center is: V = 2π kλR/√d² + R², where "k" is the constant of
electrical proportionality.
Transcribed Image Text:89. To show that the electric potential created by a very thin ring of radius "R", uniform linear charge density "2", at a point located on its axis of symmetry perpendicular to the plane of the ring, at a distance "d" from its center is: V = 2π kλR/√d² + R², where "k" is the constant of electrical proportionality.
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