Problem Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from its center? (Consider that the surface of the plate lies in the yz plane) Solution A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q. There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That shape would be a ring. So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given by E = (1/ (x0q/( 242) Since, the actual ring (whose charge is dg) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field contribution is expressed as = (1/ )(x0 2. ) We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain E = (x0/ 2.
Problem Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from its center? (Consider that the surface of the plate lies in the yz plane) Solution A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q. There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That shape would be a ring. So for a ring whose charge is q, we recall that the electric field it produces at distance x0 is given by E = (1/ (x0q/( 242) Since, the actual ring (whose charge is dg) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field contribution is expressed as = (1/ )(x0 2. ) We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain E = (x0/ 2.
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![Problem
Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from
its center? (Consider that the surface of the plate lies in the yz plane)
Solution
A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q.
There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That
shape would be a ring.
So for a ring whose charge is q. we recall that the electric field it produces at distance x0 is given by
E = (1/
)(x0q)/
24,2)
Since, the actual ring (whose charge is dg) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field
contribution is expressed as
= (1/
)(x0
We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain
E = (x0/
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6bbf7b9b-e5b7-4017-bd21-410b43d9f8b5%2F7eda1354-535d-438a-ae37-685c4a11145a%2Fny9mzbn_processed.png&w=3840&q=75)
Transcribed Image Text:Problem
Using the method of integration, what is the electric field of a uniformly charged thin circular plate (with radius R and total charge Q) at xo distance from
its center? (Consider that the surface of the plate lies in the yz plane)
Solution
A perfect approach to this is to first obtain the E-field produced by an infinitesimal charge component of the charge Q.
There will be several approaches to do this, but the most familiar to us is to obtain a very small shape that could easily represent our circular plane. That
shape would be a ring.
So for a ring whose charge is q. we recall that the electric field it produces at distance x0 is given by
E = (1/
)(x0q)/
24,2)
Since, the actual ring (whose charge is dg) we will be dealing with is an infinitesimal part of the circular plane, then, its infinitesimal electric field
contribution is expressed as
= (1/
)(x0
We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain
E = (x0/
2.
![We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain
R
E = (X0/
24
Evaluating the integral will lead us to
Qxo
1
1
E=
4 nE,R? Xo (x3 + R?) /2
For the case where in R is extremely bigger than x0. Without other substitutions, the equation above will reduce to
E = Q/(
E0)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6bbf7b9b-e5b7-4017-bd21-410b43d9f8b5%2F7eda1354-535d-438a-ae37-685c4a11145a%2F5aa351_processed.png&w=3840&q=75)
Transcribed Image Text:We wish to obtain the complete electric field contribution from the above equation, so we integrate it from 0 to R to obtain
R
E = (X0/
24
Evaluating the integral will lead us to
Qxo
1
1
E=
4 nE,R? Xo (x3 + R?) /2
For the case where in R is extremely bigger than x0. Without other substitutions, the equation above will reduce to
E = Q/(
E0)
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