char letters[26]; for(int i = 0; i < 26; i++) { letters[i] = 'A' + i; } printf("%c", letters[24]); printf("%c", *(letters + 4)); printf("S");
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Consider the code below.
char letters[26];
for(int i = 0; i < 26; i++)
{
letters[i] = 'A' + i;
}
printf("%c", letters[24]);
printf("%c", *(letters + 4));
printf("S");
What does this code print?
![](/static/compass_v2/shared-icons/check-mark.png)
Step by step
Solved in 3 steps with 1 images
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- 1) Find the errors in the following codes: int main() { } int { Hanging Indent #include ; int a = 1;b = 4; c, d C + = a++; d = 5--; printf("Please enter an inter: "); scanf("%f", num) d = (num = 0? a+b:a+b+c); sum= (a:b:c:d: a+b+c+d); printf("Sum is %d: \n", Sum); Return 0;Input 1. integer n 2. N integer values Output Enter n: 5 Enter value #1: 3 3 is odd Enter value #2: 6 6 is even Enter value # 3: 4 4 is even Enter value #4: 1 1 is odd Enter value #5: 3 3 is odd//Assignment 06 */public static void main[](String[] args) { String pass= "ICS 111"; System.out.printIn(valPassword(pass));} /* public static boolean valPassword(String password){ if(password.length() > 6) { if(checkPass(password) { return true; } else { return false; } }else System.out.print("Too small"); return false;} public static boolean checkPass (String password){ boolean hasNum=false; boolean hasCap = false; boolean hasLow = false; char c; for(int i = 0; i < password.length(); i++) { c = password.charAt(1); if(Character.isDigit(c)); { hasNum = true; } else if(Character.isUpperCase(c)) { hasCap = true; } else if(Character.isLowerCase(c)) { hasLow = true; } } return true; { return false; } }
- #include using namespace std; void scanPrice (string [], double []); // Do not modify the code double printReceipt(string [], double[]); // Do not modify the code int main () { double sum; string item [3] = {"Vegetable","Egg", "Meat"}; double price [3];| %3D scanPrice (item,price); sum = RrintReceipt (item,price); cout Price: 10 The price of Vegetable is RM 2 The price of Egg is RM 3 The price of Meat is RM 10 Your total expenses is RM 15Look at the following C++ code and comment each line about how it works with pointer. int i = 33; double d = 12.88; int * iPtr = &i; double * dPtr = &d; // iPtr = &d; // dPtr = &i; // iPtr = i; // int j = 99; iPtr = &j; //#include<stdio.h> #include<math.h> int main() { char cod; int gal; float cost; printf("Data Codes:"); printf(" \n H-Home \n C-Commercial \n I-Industrial "); printf("\nInput data code: "); scanf("%c", &cod); printf("\nInput number of water (in gallons) used: "); scanf("%d", &gal); if (cod=='H'|| cod=='h') { cost = 250+(0.002*gal); printf("\nTOTAL COST IS %.2f", cost); } else if (cod=='C'||cod=='c') { if (gal<=4000000) { printf("\nTOTAL COST IS 5000.00"); }…
- In the C programming language, if all function prototypes are listed at the top of your code, outside and above all functions, you do not need to worry about the order of the function definitions within the code. True FalseC++ Coding: ArraysTrue and False Code function definitions for eoNum() and output(): Both eoNum() and output() are recursive functions. output() stores the even/odd value in an array. Store 0 if the element in the data array is even and store 1 if the element in the data array is odd. eoNum() displays all the values in an array to the console.#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
- #include <stdio.h>#include <string.h> int findRepeat(char* s){int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++){for (j = i + 1; j < strlen(s); j++){if (s[i] == s[j]){p = i;break;}}if (p != -1)break;}return p;} int main(){char str[] = "Hello World";int pos = findRepeat(str);if (pos == -1)printf("Not found");elseprintf("%c", str[pos]);return 0;}can you please explain this code for meint main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…int main(int argc, char **argv) { float *rainfall; float rain_today; // rainfall has been dynamically allocated space for a floating point number. // Both rainfall and rain today have been initialized in hidden code. // Assign the amount in rain_today to the space rainfall points to. return 0; }
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