*Chapter 35, Problem 050ZYour answer is partially correct. Try again.Reflection by thin layers. In the figure, light is incident perpendicularly on a thin layer of material 2 that lies between(thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r and r2 interfere, and here weconsider the type of interference to be either maximum (max) or minimum (min). The table below provides the indexes ofrefraction n, n2, and n3, the type of interference, and the wavelength A in nanometers of the light as measured in air.Give the second least thickness L.ngn1n2n3Туре1.391.461.80min2nd570NumberT427.5Units hm

Given, At point 1 and point 2 reflection takes place from a rarer medium. so, there will be no phase…

Answered: *Chapter 35, Problem 050 ZYour answer…

Similar questions

Some feathers of the ruby-throated hummingbird have an iridescent green color due to interference. A simplified model of the step structure of the feather is shown in the figure. If the strongest reflection for normal incidence is at ) = 530 nm, what is the step height h? Assume h has the smallest possible value. Air nm
Your boss calls you in his office and hands you the plot shown below. The plot represent data of reflection coefficient for an EM-wave at oblique incidence. It includes the index of refraction of the second medium (n2) and also an angle that your boss does not understand what it is. Your boss tells you that in 30 min, the customer will call back and wants the following information: 1. What polarization has been used to obtain the data 2. What is the index of refraction of the first medium and whether or not is an external or internal reflection. 3. What does the number right above the x-axis represent. 1.5 n;= 3 0.5 41.42 -0.5 10 20 30 40 50 60 70 80 90 Angle of incidence Reflection Coefficients
please help: Antireflection Coating A glass lens (nglass=1.52) has an antireflection coating of MgF2(n=1.38). A) For 548-nm light, what minimum thickness of MgF2 will cause the reflected rays R2 and R4 (see figure) to interfere destructively, assuming normal incidence? Express your answer to three significant figures. B) Interference will also occur between the forward-moving rays R1 and R3 in the figure. What minimum thickness of MgF2 will cause these two rays to interfere constructively? Express your answer to three significant figures.
** 35. A mirror is to be designed that will reflect infrared laser light of wavelength 1064 nm. The designer chooses a thin layer of magnesium fluoride to coat a plane slab of glass. The
Calculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o Answers: r = 8.2o , c = 78.4o , i = 81.8o light will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nị
please answer both please
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 10 17 m away from you and 6 × 10 9 m from each other. You are measuring light with a wavelength of 700 nm. As the light goes through the lens, it diffracts. a. Is it possible, using this telescope, to see the two stars as separate stars? b. What is the minimum possible lens diameter you would need in order to resolve these two stars?
You have been tasked with designing an anti-reflective coating for a camera lens. If the material you are using for the thin film, the antireflective coating has an n=1.38, and a coating is designed to eliminate reflected light of 550 nm in air when incident normally on glass (n=1.50), what thickness should the film be? A: what color would the lens look like B: why does this effect indicate that light behaves like a wave I already know the thickness, it is 99.6. I need help with parts A and B.