CHAPTER 3 Graphical Analysis of Motion PRACTICE EXERCISES Bus Trip 200 180 in 160 140 120 100 80 60 40 20 0. 2 4 8 10 12 Time (hr) Given the position-time graph, find the displacement (distance and direction) of the bus: Given the position-time graj the velocity (speed and direc the bus: 2. from t = o.0 hr to t = 2.0 hr from t = 0.0 hr to t = 2.0 a. %3D a. b. from t = 2.0 hr to t = 4.0 hr b. from t 2.0 hr to t = 4.0 from t = 4.0 hr to t = 6.c %3D from t = 4.0 hr to t = 6.0 hr from t = 8.0 hr to t = 10.0 hr с. %3D с. %3D d. d. from t = %3D 6.0 hr to t = 8.c %3D from t = 10.0o hr to t = 12.0 hr from t = 8.0 hr to t = 10 e. e. Position (km, north)
CHAPTER 3 Graphical Analysis of Motion PRACTICE EXERCISES Bus Trip 200 180 in 160 140 120 100 80 60 40 20 0. 2 4 8 10 12 Time (hr) Given the position-time graph, find the displacement (distance and direction) of the bus: Given the position-time graj the velocity (speed and direc the bus: 2. from t = o.0 hr to t = 2.0 hr from t = 0.0 hr to t = 2.0 a. %3D a. b. from t = 2.0 hr to t = 4.0 hr b. from t 2.0 hr to t = 4.0 from t = 4.0 hr to t = 6.c %3D from t = 4.0 hr to t = 6.0 hr from t = 8.0 hr to t = 10.0 hr с. %3D с. %3D d. d. from t = %3D 6.0 hr to t = 8.c %3D from t = 10.0o hr to t = 12.0 hr from t = 8.0 hr to t = 10 e. e. Position (km, north)
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![CHAPTER 3
Graphical Analysis of Motion
TRAS
PRACTICE EXERCISES
Bus Trip
200
180
160
140
120
100
80
60
40
20
4
6.
8
10 12
Time (hr)
Given the position-time graph, find
the displacement (distance and
direction) of the bus:
Given the position-time grap
the velocity (speed and direc
the bus:
2.
from t = 0.0 hr to t = 2.0 hr
from t = 0.0 hr to t = 2.0
a.
%3D
а.
%3D
b.
from t = 2.0 hr to t = 4.0 hr
b.
from t = 2.o hr to t = 4.0
%3D
C.
from t = 4.0 hr to t = 6.0 hr
from t =
%3D
%3D
C.
4.0 hr to t = 6.0
from t = 6.0 hr to t = 8.0
%3D
d.
from t = 8.0 hr to t = 10.0 hr
d.
%3D
%3D
%3D
from t = 10.o hr to t = 12.0 hr
from t = 8.0 hr to t = 10.
e.
%3D
е.
Position (km, north)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69e60e97-4558-4df0-b9e7-d909b7c60181%2F1276e23c-c2ca-4da6-8d0a-c6ee5415c811%2F6vtb69_processed.jpeg&w=3840&q=75)
Transcribed Image Text:CHAPTER 3
Graphical Analysis of Motion
TRAS
PRACTICE EXERCISES
Bus Trip
200
180
160
140
120
100
80
60
40
20
4
6.
8
10 12
Time (hr)
Given the position-time graph, find
the displacement (distance and
direction) of the bus:
Given the position-time grap
the velocity (speed and direc
the bus:
2.
from t = 0.0 hr to t = 2.0 hr
from t = 0.0 hr to t = 2.0
a.
%3D
а.
%3D
b.
from t = 2.0 hr to t = 4.0 hr
b.
from t = 2.o hr to t = 4.0
%3D
C.
from t = 4.0 hr to t = 6.0 hr
from t =
%3D
%3D
C.
4.0 hr to t = 6.0
from t = 6.0 hr to t = 8.0
%3D
d.
from t = 8.0 hr to t = 10.0 hr
d.
%3D
%3D
%3D
from t = 10.o hr to t = 12.0 hr
from t = 8.0 hr to t = 10.
e.
%3D
е.
Position (km, north)
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