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change in ell. e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2+Ni reaction if the Hg/Hgz2+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg2 half-cell is assigned a reduction potential of -0.80 volts? Hg/Hg;+ is 0.00 V: -1.04 +2

change in ell. e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2+Ni reaction if the Hg/Hgz2+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg2 half-cell is assigned a reduction potential of -0.80 volts? Hg/Hg;+ is 0.00 V: -1.04 +2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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ENITNI = F0- 0.0s9iv d) Does the cell potential change if the reaction were written for two moles of Ni(s) reacting? Write the redox reaction using a factor of two moles and answer the question using the Nernst equation. Explain 2Ni 6)+ 2 Hg rag) loon > 2 Hg les + N, "caq) - -D151V-0.0591v 24 2NiLs)-2Nlaq,+4e 0,257v n'will also change from 21p 4 io pethest reactior, So there wll not be any.change e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2*Ni reaction if the Hg/Hg2+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg2 half-cell is assigned a reduction potential of -0.80 volts? in ell. Hg/Hgz2* is 0.00 V: -1.04 Hg/Hg,2* is -0.80 V: E cell = Em /Ni 104U=-0.80v – Eniz m - ENi INI= 1.84 Eniz4 INi=-1.84 V
Transcribed Image Text:ENITNI = F0- 0.0s9iv d) Does the cell potential change if the reaction were written for two moles of Ni(s) reacting? Write the redox reaction using a factor of two moles and answer the question using the Nernst equation. Explain 2Ni 6)+ 2 Hg rag) loon > 2 Hg les + N, "caq) - -D151V-0.0591v 24 2NiLs)-2Nlaq,+4e 0,257v n'will also change from 21p 4 io pethest reactior, So there wll not be any.change e) If the cell potential as measured is 1.04 volts, what would be the reduction potential associated with the Ni2*Ni reaction if the Hg/Hg2+ half-cell is assigned a potential of 0.00 V? Repeat the question: if the Hg/Hg2 half-cell is assigned a reduction potential of -0.80 volts? in ell. Hg/Hgz2* is 0.00 V: -1.04 Hg/Hg,2* is -0.80 V: E cell = Em /Ni 104U=-0.80v – Eniz m - ENi INI= 1.84 Eniz4 INi=-1.84 V
b) If the reaction occurs spontaneously in the cell, which electrode is the anode? Explain. Oxid ation of Ni Occurs, so anode is J Ni s) c) Calculate the standard cell potential, E°. Ni 24 E°= 0.789 -(-0.25) Ni Ha 0789 Hg
Transcribed Image Text:b) If the reaction occurs spontaneously in the cell, which electrode is the anode? Explain. Oxid ation of Ni Occurs, so anode is J Ni s) c) Calculate the standard cell potential, E°. Ni 24 E°= 0.789 -(-0.25) Ni Ha 0789 Hg
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