Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,...9 val a1 = #1 L2; val a2 = hd (al); val a3 = #1 a2; val a4 = hd a3; to get 1, combine the above val aa hd (#1 (hd (#1 L2))); = (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Challenging, beyond recursion practice in this class, just an exercise to
dissect hybird structure of tuples and lists
val L1 = [1, 2, 3, 4, 5, 6, 7];
val L2 = ([([1,2],3), ([4,5,6],7)], (8,9));
Construct the following by ONE expression
try ::nil style instead of []
Hint: try one at a time, figure out expressions for 1,2,...9
val a1 = #1 L2;
val a2 = hd (al);
val a3 = #1 a2;
val a4 = hd a3;
to get 1, combine the above
val aa = hd (#1 (hd (#1 L2)));
(1) [(3,6), (4,2)] from L1
(2) ([2], (3,[5])) from L1
(3) [2,3,5] from L2
(4) (8,4,2,1) from L2
Transcribed Image Text:Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,...9 val a1 = #1 L2; val a2 = hd (al); val a3 = #1 a2; val a4 = hd a3; to get 1, combine the above val aa = hd (#1 (hd (#1 L2))); (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2
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