CHALLENGE ACTIVITY5.8.1: Nested loops: Print rectangle Given the number of rows and the number of columns, write nested loops to print a rectangle.Sample output with inputs: 2 3 * * ** * * Use Python, please. 344614.2153518.qx3zqy71 num_rows = int(input())2 num_cols = int(input())1 testpassed4 ' Your solution goes here '''5All testsprint('*', end=' ')print()passed7RunFeedback?

PROGRAM CODE: # Python Program to Print Rectangle Star Pattern# take number of rows from the…

CHALLENGE ACTIVITY 5.8.1: Nested loops: Print rectangle Given the number of rows and the number of columns, write nested loops to print a rectangle. Sample output with inputs: 2 3 * * * * * * Use Python, please.

CHALLENGE ACTIVITY 5.8.1: Nested loops: Print rectangle Given the number of rows and the number of columns, write nested loops to print a rectangle. Sample output with inputs: 2 3 * * * * * * Use Python, please.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?
bool validPassword=true; cin >> passPhrase;} if (passPhrase.length() <= 4) { validPassword = false; } else { int digitCount=0; for (int i = 0; i < passPhrase.length(); i++) { if (isdigit(passPhrase.at(i))) digitCount++; } if (digitCount > 4) { validPassword=false; } if (validPassword) { cout << "Valid" << endl; } else { cout << "Invalid" << endl; } return 0;} // it still comes up with these errors. Not sure what it is telling me. main.cpp:9:7: error: expected unqualified-id before ‘if’ 9 | if (passPhrase.length() <= 4) { | ^~ main.cpp:13:7: error: expected unqualified-id before ‘else’ 13 | else { | ^~~~
In java, the Arrays class contains a static binarySearch() method that returns …… if element is found. false true (-k–1) where k is the position before which the element should be inserted The index of the element
void radixSort(int arr[], int n) { intm=getMax(arr, n); for (intexp=1; m/exp>0; exp*=10) countSort(arr, n, exp); } void printData(int arr[], int start, int len) { if( start>=len ) return( 0 ); printf("%d\n", arr[start]); printData(arr, start+1, len); } int main() { intarr[]= {8, 9, 3, 4, 7, 2, 5, 6, 1}; intn=sizeof(arr) /sizeof(arr[0]); radixSort(arr, n); printData(arr, 0, n); return0; } In MIPS
extern "C" int f(int *,int,int); int a[2][2] = {{11,12},{21,22}}; void setup(){ Serial.begin(115200); while(!Serial); delay(500); int *arr = (int*)a; Serial.println(f(arr,2,2)); } void loop(){ } .global f f: ldr r3,[r0] // get first element mov r2,#0add r2,r3 mov r1, #3 lp: add r0,#4 // add next elementldr r3,[r0]add r2,r3sub r1,#1 bgt lp mov r0,r2 bx lr Describe what operation is being performed in this code
function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))
void ExtractMinimumWeightPath(int path[MAX], int weights[MAX][MAX], int pathWeights[MAX][MAX], int rowc, int colc){int rowsCount = rowc;int colsCount = colc;path[rowsCount];int col = 0;int i = 0;for(i=1;i<colsCount;i++){if(pathWeights[rowsCount-1][i]<pathWeights[rowsCount-1][col]){col = i;}} int row = rowsCount-1;do{path[row] = col + 1;if (col>0 && pathWeights[row-1][col-1] + weights[row][col] == pathWeights[row][col]){col = col - 1;} else if (col < colsCount-1 && pathWeights[row-1][col+1] + weights[row][col] == pathWeights[row][col]){col = col + 1;}row--;} while(row>0);path[0] = col + 1;} This is a code in C, I need to change the code as much as possible, but on condition to perform the same work as this. Changing the var names and the loops is enough
public void OnSend(View v){ String phoneNumber = number.getText().toString(); String smsmessage = message.getText().toString(); if(phoneNumber == null || phoneNumber.length() == 0 || smsmessage == null || smsmessage.length() == 0){ return; } if(checkPermission(Manifest.permission.SEND_SMS)){ SmsManager smsManager = SmsManager.getDefault(); smsManager.sendTextMessage(phoneNumber, null, smsmessage, null, null); Toast.makeText(this, "Message sent", Toast.LENGTH_SHORT).show(); } Question 2: Explain the following code: button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { FragmentManager fm = getSupportFragmentManager(); FragmentTransaction ft = fm.beginTransaction(); XFragment xfragment = new XFragment(); ft.add(R.id.Main_fragment, xfragment);…
public class testRun{public static int find(int[] data, int target,int start, int end) {int[] stored = sort(data);if (start <= end) {int midPoint = (start + end / 2);if (stored[midPoint] == target) {return midPoint;}if (stored[midPoint] > target) {return find(data, target, start, midPoint - 1);//return first half,exclusive itself}if (stored[midPoint] < target) {return find(data, target, start, midPoint + 1);//return last half,exclusive itself.}}return -1;}public static int[] sort(int[] data){// Find the smallest element in the listfor (int i = 0; i < data.length -1 ; i++){ //generate the index position,not =< b/c goes outer boundint min = i; //assign index position to min in each iterationfor (int j = i + 1; j < data.length ; j++){if (data[j] < data[min]){ //if the element in the second index number smaller than// the element in previous index numbermin = j; // assign j to the smallest number}}swap (data,i,min);// data[i] = min the smallest number assign to…
My queston is for c programming. As the user add 5 different values in array CS_arr if there will any same value entered by the user before, as for a new value. And then when all the values collected, print them all.Test Case:3.2 -2.0 0 -2.0 4 The index 1 and index 4 have the same value, please add another set of values3.2 -2.0 0 4 100The print of your entered value is:3.2 -2.0 0 4 100
in c++ vs19: Go on https://www.imdb.com/ and look up for some movies. Select at least 10 movies. For each movie you choose, store its title into an array called movies and its rate (score) into a second array called ratings. The same information for a single movie must be stored in elements having the same index in the two arrays. For example, if Jurassic Park is the third movie you choose, then both its title and its rate should have index 2.movies[2] = "Jurassic Park";rating[2] = 8.1;Once you filled your arrays, print the list of all the movies from the highest score to the lowest. Follow this format:number_in_ranking. movie_title (movie_rate) newlineIf two movies have the same rate, their order doesn’t matter.Note: You cannot use structs, you cannot use classes, you cannot use matrices, you cannot use advanced data structures, you cannot use std::swap.Note: You can use templates if you need to.Remember to comment the code such that it is easy for other developers to understand…
40.|Asiacell docs.google.com/forms :D yuustivi بل اجابة هذا السؤال بشكل PDF Describe the difference between tl .following two progran class Progarml { public static void main(String[] args) { int[] a = {1, 2}: q3(a); System.out.println( a[0]+ " " +a[1]);} class Program2 { public static void main(String[] args) { int[] a = {1, 2}; q3(a[0], a[ 1]); System.out.println(a[0]+ " "+ a[1]);} static void swap(int[] a) { int t = a[0]: a[0] = a[1]: a[1] = t:} static void q3(int n1, int n2) { int t =n1; nl = n2; n2 = t;} إضافة ملف 4 صفحة 3 من التالي Es ل كلمات المرور عبر نماذج Google مطلقًا.