CH4(g) + 2 Cl2(g) → CH2C12(g) + 2 HCI(g) CH4 reacts with Cl2 as shown by the equation above. A chemist adds 1.35 moles of CH4 is placed in a reaction vessel containing 3.58 mol of Cl2(g). (a) Identify the limiting reactant. Justify your answer with a calculation. (b) Calculate the total number of moles of CH2CI2(g) in the container after the limiting reactant has been totally consumed. (c) Calculate the total moles of the excess reactant left over. (d) If 0.95 moles of CH,Cl, are produced in the lab, what is the percent yield?

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CH4(g) + 2 Cl2(g) → CH2C12(g) + 2 HCI(g)
CH4 reacts with Cl2 as shown by the equation above. A chemist adds 1.35 moles of CH4 is placed in a reaction vessel
containing 3.58 mol of Cl2(g).
(a) Identify the limiting reactant. Justify your answer with a calculation.
(b) Calculate the total number of moles of CH2CI>(g) in the container after the limiting reactant has been totally
consumed.
(c) Calculate the total moles of the excess reactant left over.
(d) If 0.95 moles of CH,Cl, are produced in the lab, what is the percent yield?
Transcribed Image Text:CH4(g) + 2 Cl2(g) → CH2C12(g) + 2 HCI(g) CH4 reacts with Cl2 as shown by the equation above. A chemist adds 1.35 moles of CH4 is placed in a reaction vessel containing 3.58 mol of Cl2(g). (a) Identify the limiting reactant. Justify your answer with a calculation. (b) Calculate the total number of moles of CH2CI>(g) in the container after the limiting reactant has been totally consumed. (c) Calculate the total moles of the excess reactant left over. (d) If 0.95 moles of CH,Cl, are produced in the lab, what is the percent yield?
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