CH3CH₂COOH(aq) + H₂O2(aq) ←→CH3CH₂COOOH(aq) Propionic Acid HP PPA AH-4.12 kJ/mol This reaction takes place in two steps: S1 (fast): S2 (slow): Ep Ke 298 K= 2.05 Ea (slow step) = 44.2 kJ CH3CH:COOH(aq) + H*(aq) → CH3CH₂COOH: (aq) CH3CH₂COOH: (aq) + H₂O₂(aq) → CH₂CH₂COOH(aq) + H*(aq) Str 7. Which of the following energy diagrams likely corresponds to the synthesis of PPA? a. b. C. d. Ep Ep ·M·M·-|M |M Reaction Progress Reaction Progress Reaction Progress Reaction Progress Ep
CH3CH₂COOH(aq) + H₂O2(aq) ←→CH3CH₂COOOH(aq) Propionic Acid HP PPA AH-4.12 kJ/mol This reaction takes place in two steps: S1 (fast): S2 (slow): Ep Ke 298 K= 2.05 Ea (slow step) = 44.2 kJ CH3CH:COOH(aq) + H*(aq) → CH3CH₂COOH: (aq) CH3CH₂COOH: (aq) + H₂O₂(aq) → CH₂CH₂COOH(aq) + H*(aq) Str 7. Which of the following energy diagrams likely corresponds to the synthesis of PPA? a. b. C. d. Ep Ep ·M·M·-|M |M Reaction Progress Reaction Progress Reaction Progress Reaction Progress Ep
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given reaction is oxidation reaction of propionic acid into peroxy propionic acid which is taking place in two steps. First step is the fast step and second step is the slowest step of the reaction. On the basis of given information we have to draw the energy profile of the given reaction.
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