Ch-6 1. The first known correct software solution to the critical-section problem for n processes with a lower bound on waiting of n-1 turns was presented by Eisenberg and McGuire. The processes share the following variables: enum pstate (idle, want_in, in_cs), pstate flag[n]; int turn; All the elements of flag are initially idle. The initial value of turn is immaterial (between 0 and n-1). The structure of process P/ is shown in the following Figure. Prove that the algorithm satisfies all three requirements for the critical-section problem. do { while (true) { } flag[i] j-turn; while (j = 1) { if (flag[j] = idle) { vant.in; j - turn; else j - (j + 1) % n; } flag[i] in.cs; j = 0; while ((j
Ch-6 1. The first known correct software solution to the critical-section problem for n processes with a lower bound on waiting of n-1 turns was presented by Eisenberg and McGuire. The processes share the following variables: enum pstate (idle, want_in, in_cs), pstate flag[n]; int turn; All the elements of flag are initially idle. The initial value of turn is immaterial (between 0 and n-1). The structure of process P/ is shown in the following Figure. Prove that the algorithm satisfies all three requirements for the critical-section problem. do { while (true) { } flag[i] j-turn; while (j = 1) { if (flag[j] = idle) { vant.in; j - turn; else j - (j + 1) % n; } flag[i] in.cs; j = 0; while ((j
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Ch-6
1. The first known correct software solution to the critical-section problem for n processes with a lower bound on waiting of n − 1 turns was presented by Eisenberg and McGuire. The processes share the following variables:
enum pstate { idle, want_in, in_cs}; pstate flag[n];
int turn;
All the elements of flag are initially idle. The initial value of turn is immaterial (between 0 andn-1).ThestructureofprocessPi isshowninthefollowingFigure.Provethatthe algorithm satisfies all three requirements for the critical-section problem.
![Ch-6
1. The first known correct software solution to the critical-section problem for 77 processes with
a lower bound on waiting of 77- 1 turns was presented by Eisenberg and McGuire. The
processes share the following variables:
enum pstate (idle, want_in, in_cs};
pstate flag[n];
int turn;
All the elements of flag are initially idle. The initial value of turn is immaterial (between 0
and n-1). The structure of process P/ is shown in the following Figure. Prove that the
algorithm satisfies all three requirements for the critical-section problem.
do {
while (true) {
flag[i] = want_in;
j= turn;
while (j = i) {
if (flag[j] = idle) {
j = turn;
else
j
(j+1) % n;
}
flag[i] = in.cs;
j = 0;
while ((j<n) && (j == i || flag[j] != in.cs))
j++;
if ( (j >= n) && (turn == i || flag [turn] == idle))
break;
}
/* critical section */
j= (turn + 1) % n;
while (flag [j] == idle)
j = (j + 1) % n;
turn = j;
flag[i] = idle;
/* remainder section */
} while (true);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F851230c5-e9d9-45df-bb53-600d0a184468%2F53ca22bb-62b0-4250-8bfb-51b987bf36c0%2Fpr0zpo_processed.png&w=3840&q=75)
Transcribed Image Text:Ch-6
1. The first known correct software solution to the critical-section problem for 77 processes with
a lower bound on waiting of 77- 1 turns was presented by Eisenberg and McGuire. The
processes share the following variables:
enum pstate (idle, want_in, in_cs};
pstate flag[n];
int turn;
All the elements of flag are initially idle. The initial value of turn is immaterial (between 0
and n-1). The structure of process P/ is shown in the following Figure. Prove that the
algorithm satisfies all three requirements for the critical-section problem.
do {
while (true) {
flag[i] = want_in;
j= turn;
while (j = i) {
if (flag[j] = idle) {
j = turn;
else
j
(j+1) % n;
}
flag[i] = in.cs;
j = 0;
while ((j<n) && (j == i || flag[j] != in.cs))
j++;
if ( (j >= n) && (turn == i || flag [turn] == idle))
break;
}
/* critical section */
j= (turn + 1) % n;
while (flag [j] == idle)
j = (j + 1) % n;
turn = j;
flag[i] = idle;
/* remainder section */
} while (true);
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