Ceva's Theorem: Let AD, BE and CF be cevians for AABC. AF AD, BE and CF are concurrent or parallel + FB BD СЕ = +1. DC ΕΑ

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Ceva's Theorem: Let AD, BE and CF be cevians for AABC.
AF BD
CE
AD, BE and CF are concurrent or parallel 4
FB
= +1.
DC
EA
The proof of this theorem is quite long, so we will first learn how to use the theorem.
Example: In the picture below, cevians AD, BE and CF are concurrent at G inside AABC, so by
Ceva's Theorem
AF
+1 =
FB
BD
СЕ
DC
EA
= (x/
→ x =
А
7
F
E
G
8
B
6
D
7
Transcribed Image Text:Ceva's Theorem: Let AD, BE and CF be cevians for AABC. AF BD CE AD, BE and CF are concurrent or parallel 4 FB = +1. DC EA The proof of this theorem is quite long, so we will first learn how to use the theorem. Example: In the picture below, cevians AD, BE and CF are concurrent at G inside AABC, so by Ceva's Theorem AF +1 = FB BD СЕ DC EA = (x/ → x = А 7 F E G 8 B 6 D 7
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