Centerville is located at (8,0) in the xy-plane, Springfield is at (0,5), and Shelbyville is at (0,-5). To save on the cost of cable, Greedy Cablevision wants to arrange the cable in a Y-shaped configuation, running cable from Centerville to some point (x,0) on the x-axis where it then splits into two branches, one going to Springfield and one to Shelbyville. Find the location (x,0) that will minimize the amount of cable between the 3 towns and compute the amount of cable needed. Justify your conclusion by answering the following questions. The following diagram is useful: f(x)=x-8+2√x² +25 (b) We find that f(x) has a critical point at Springfield (0,5) Shelbyville (0,5) x= (,0) (a) To solve this problem we need to minimize the following function of x: (Click on the graph to enlarge it.) Centerville (8,0) 5√3 3 (c) To verify that f(x) has a minimum at this critical point we evaluate the second derivative f"(x) at this point.

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Springfield and Shelbyville. There
needs to be cable connecting Centerville to both towns.
Centerville is located at (8,0) in the xy-plane, Springfield is at (0,5), and Shelbyville is at (0,-5). To save on the cost of cable, Greedy Cablevision wants to arrange
the cable in a Y-shaped configuation, running cable from Centerville to some point (x,0) on the x-axis where it then splits into two branches, one going to
Springfield and one to Shelbyville.
Find the location (x,0) that will minimize the amount of cable between the 3 towns and compute the amount of cable needed. Justify your conclusion by
answering the following questions. The following diagram is useful:
f(x)=x-8+2√x² +25
2
(b) We find that f(x) has a critical point at
5√3
3
x=
Springfield (0,5)
Shelbyville (0,5)
(a) To solve this problem we need to minimize the following function of x:
f" (critical point) is
(x,0)
a positive number.
(Click on the graph to enlarge it.)
(c) To verify that f(x) has a minimum at this critical point we evaluate the second derivative f"(x) at this point.
5√3
3
(d) Thus the minimum length of cable needed is 5√3-8
Centerville (8,0)
Transcribed Image Text:Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Springfield and Shelbyville. There needs to be cable connecting Centerville to both towns. Centerville is located at (8,0) in the xy-plane, Springfield is at (0,5), and Shelbyville is at (0,-5). To save on the cost of cable, Greedy Cablevision wants to arrange the cable in a Y-shaped configuation, running cable from Centerville to some point (x,0) on the x-axis where it then splits into two branches, one going to Springfield and one to Shelbyville. Find the location (x,0) that will minimize the amount of cable between the 3 towns and compute the amount of cable needed. Justify your conclusion by answering the following questions. The following diagram is useful: f(x)=x-8+2√x² +25 2 (b) We find that f(x) has a critical point at 5√3 3 x= Springfield (0,5) Shelbyville (0,5) (a) To solve this problem we need to minimize the following function of x: f" (critical point) is (x,0) a positive number. (Click on the graph to enlarge it.) (c) To verify that f(x) has a minimum at this critical point we evaluate the second derivative f"(x) at this point. 5√3 3 (d) Thus the minimum length of cable needed is 5√3-8 Centerville (8,0)
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