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a. What is the particle's velocity at time t = 3? The velocity is (1). because v(t)= (2) - b. Is the acceleration of the particle at time t=2 positive or negative? The acceleration is (3). c. What is the particle's position at time t=2? The particle's position is because a(t)= (4). (5). because s(t)= (6).

a. What is the particle's velocity at time t = 3? The velocity is (1). because v(t)= (2) - b. Is the acceleration of the particle at time t=2 positive or negative? The acceleration is (3). c. What is the particle's position at time t=2? The particle's position is because a(t)= (4). (5). because s(t)= (6).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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5. Suppose that f is the differentiable function shown in the graph on the right and that the position at time t (sec) of a particle moving along a coordinate axis is -fr(x) dx Sa dx meters. Use the graph to answer parts (a) through (g). a. What is the particle's velocity at time t=3? The velocity is (1)- because v(t)= (2) - b. Is the acceleration of the particle at time t = 2 positive or negative? The acceleration is (3). c. What is the particle's position at time t=2? At time t = because a(t)= (4)- The particle's position is (5)- d. At what time during the first 9 sec does s have the largest value? (7). e. Approximately when is the acceleration zero? because s(t)= (6) - The particle is moving toward the origin between t = on this interval. At time t=8, the particle is to (15). sec. The acceleration is zero at t= (Type a whole number. Use a comma to separate answers as needed.) f. When is the particle moving toward the origin? Away from the origin? because after that time, the region lies (8). (12). The particle is moving away from the origin between t = (13) is (14). on this interval. g. On which side of the origin does the particle lie at time t = 8? because a(t)= (10). because (16) and t= 12- and t = -3--- 3+(1.3) (3,9) is (17)- (2.6) y-Ex 12 3 45 since (11). since (5,6) 789 the x-axis. at time t = 8
Transcribed Image Text:5. Suppose that f is the differentiable function shown in the graph on the right and that the position at time t (sec) of a particle moving along a coordinate axis is -fr(x) dx Sa dx meters. Use the graph to answer parts (a) through (g). a. What is the particle's velocity at time t=3? The velocity is (1)- because v(t)= (2) - b. Is the acceleration of the particle at time t = 2 positive or negative? The acceleration is (3). c. What is the particle's position at time t=2? At time t = because a(t)= (4)- The particle's position is (5)- d. At what time during the first 9 sec does s have the largest value? (7). e. Approximately when is the acceleration zero? because s(t)= (6) - The particle is moving toward the origin between t = on this interval. At time t=8, the particle is to (15). sec. The acceleration is zero at t= (Type a whole number. Use a comma to separate answers as needed.) f. When is the particle moving toward the origin? Away from the origin? because after that time, the region lies (8). (12). The particle is moving away from the origin between t = (13) is (14). on this interval. g. On which side of the origin does the particle lie at time t = 8? because a(t)= (10). because (16) and t= 12- and t = -3--- 3+(1.3) (3,9) is (17)- (2.6) y-Ex 12 3 45 since (11). since (5,6) 789 the x-axis. at time t = 8
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