center-to-center spacing of struts in the plan = 5

Q: Q=400KN Ground Level 38° #16KN.m3 K=0.90 5m Dense Sand tan-0.45 N-80 Saturated Sand 38° 4m…

A: Given a soil profile consisting of dense sand for the top 5 m, saturated sand for next 4 m and hard…

Q: Use Khosla's theory (Equations and curves) to calculate the percentage uplift pressure at points C1,…

A: Solution:

Q: A wall foundation( 1.3) m wide located at a depth of 0.8 m on a saturated soil…

A: Given : Width of foundation= 1.3 m Depth of foundation = 0.8 m ϕ=26° c=38 kN/m2 γsat=19.90 kN/m3…

Q: A strip footing 1.5 m wide is located at a depth of 0.75 m (equal to the foundation thickness) in a…

A: Width of strip footing = 1.5m , Depth = 0.75m = Thickness of foundation , Unit weight of sand =…

Q: Q₁: Determine the stability of the concrete gravity retaining wall shown in Figure (1) with respect…

A:

Q: A reinforced concrete retaining wall is proportioned as shown below. There is a water table located…

A: Solution Data given: Bulk unit weight, γ = 16.93 Submerged unit weight, γsat = 9.67 Angle of…

Q: Using Rankine's carth pressures and neglecting the passive resistance, determine the safety factor…

A: Given a gravity retaining wall of height 6 m Top width = 0.5 m and bottom width = 2.5 m Figure is as…

Q: 10.10 Determine the factor of safety against bottom heave for the braced cut described in Problem…

A: Fig given above with data's and it has been asking to determine the factor of safety against bottom…

Q: Calculate the equivalent spherical diameter of a 10 μm cube, using equivalence by: perimeter,…

A: Cube of size (x) = 10µm Equivalent Spherical diameter of cube, using equivalence by 1) Perimeter = ?…

Q: 0.00 m -10.00 m -18.00 m Ysat 17.0 kN/m³ = Ysat 18.0 kN/m³ = 6.00 m Cu-50 kPa, c'=5 kPa and '= 25°…

A:

Q: Define Presumptive Bearing Pressures. Where does their orgin lies?

A: The presumptive bearing pressure is defined as the the permissible pressure or capacity which is…

Q: A 36 ft. deep excavation is supported by a sheet pile system. Strut bracing and walers are located…

A: Given  γsoil=110 pcf ,c=0H=36ftϕ=30° Horizontal c/c spacing=16ft

Q: A square spread footing supports a square tied column as shown. Assume that the reinforced concrete…

A: (1) Compute for eccentricity, e = Mu / PuSTEP 1: Calculate Mu and Pu based on load combination, U =…

Q: Using Rankine’s earth pressures and neglecting the passive resistance, determine the factor of…

A: Given:  The unit weight of concrete is 24 kN/m3. And, δ'=23ϕ'

Q: Assuming a sheet pile wall is constructed to retain 12.5m of soil, as shown in Figure 2, and the…

A:

Q: A bearing wall for a building is to be located close to a slope. The soil has a unit weight of 15.02…

A: Slope stability is the process of calculating and assessing how much stress a particular slope can…

Q: KN The square footing below is built on saturated sand with Ysat = 20 and Ø' = 30°. If the…

A: Given: Square footing dimension, 3 m x 3 m Internal friction, ϕ=30o Saturated unit weight of the…

Q: Find the stress beneath Point B of the 40 ft by 80 ft. L-Shaped flexible 1) mat foundation at depth…

A: Given Data: Size of Mat is 40 ft x 80 ft. Mat loading is w=200 psf. Depth Z=20 ft.

Q: the retaining wall shown is supporting a horizonatl backfill having a unit weight of 18.88 kN/m^3…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.