Cell Phone Call Lengths The average local cell phone call length was reported to be 2.32 minutes. A random sample of 23 phone calls showed an average of 2.86 minutes in length with a standard deviation of 0.94 minute. At a 0.01, can it be concluded that the average differs from the population average? Assume that the population is approximately normally tu (a) State the hypotheses and identify the claim. Ho = 2.32 not claim H₁ 2.32 claim
Cell Phone Call Lengths The average local cell phone call length was reported to be 2.32 minutes. A random sample of 23 phone calls showed an average of 2.86 minutes in length with a standard deviation of 0.94 minute. At a 0.01, can it be concluded that the average differs from the population average? Assume that the population is approximately normally tu (a) State the hypotheses and identify the claim. Ho = 2.32 not claim H₁ 2.32 claim
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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8.3 #4
P Value and Awnser whether to reject null hypothesis or not ?

Transcribed Image Text:**Educational Website Content**
### Statistical Hypothesis Testing
**Example Problem: Cell Phone Call Lengths**
The average duration of local cell phone calls is reported to be 2.32 minutes. A random sample of 23 phone calls showed an average length of 2.86 minutes with a standard deviation of 0.94 minute. At a significance level of \(\alpha = 0.01\), can it be concluded that the average differs from the population average? Assume normal distribution.
**Steps to Solve:**
(a) **State the Hypotheses and Identify the Claim:**
- Null Hypothesis (\(H_0\)): \(\mu = 2.32\) (not claim)
- Alternative Hypothesis (\(H_1\)): \(\mu \neq 2.32\) (claim)
This test is a two-tailed test.
**Determine the P-value:**
P-value = _______
**Decision Rule:**
Based on the calculated P-value, decide whether to reject the null hypothesis (\(H_0\)).
**Question: Reject Null Hypothesis or not?**
Analyze the results based on the significance level \(\alpha = 0.01\).
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