Cell Phone Call Lengths The average local cell phone call length was reported to be 2.32 minutes. A random sample of 23 phone calls showed an average of 2.86 minutes in length with a standard deviation of 0.94 minute. At a 0.01, can it be concluded that the average differs from the population average? Assume that the population is approximately normally tu (a) State the hypotheses and identify the claim. Ho = 2.32 not claim H₁ 2.32 claim

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8.3 #4 P Value and Awnser whether to reject null hypothesis or not ?
**Educational Website Content**

### Statistical Hypothesis Testing

**Example Problem: Cell Phone Call Lengths**

The average duration of local cell phone calls is reported to be 2.32 minutes. A random sample of 23 phone calls showed an average length of 2.86 minutes with a standard deviation of 0.94 minute. At a significance level of \(\alpha = 0.01\), can it be concluded that the average differs from the population average? Assume normal distribution.

**Steps to Solve:**

(a) **State the Hypotheses and Identify the Claim:**

- Null Hypothesis (\(H_0\)): \(\mu = 2.32\) (not claim)
- Alternative Hypothesis (\(H_1\)): \(\mu \neq 2.32\) (claim)

This test is a two-tailed test.

**Determine the P-value:**

P-value = _______

**Decision Rule:**

Based on the calculated P-value, decide whether to reject the null hypothesis (\(H_0\)).

**Question: Reject Null Hypothesis or not?** 

Analyze the results based on the significance level \(\alpha = 0.01\).
Transcribed Image Text:**Educational Website Content** ### Statistical Hypothesis Testing **Example Problem: Cell Phone Call Lengths** The average duration of local cell phone calls is reported to be 2.32 minutes. A random sample of 23 phone calls showed an average length of 2.86 minutes with a standard deviation of 0.94 minute. At a significance level of \(\alpha = 0.01\), can it be concluded that the average differs from the population average? Assume normal distribution. **Steps to Solve:** (a) **State the Hypotheses and Identify the Claim:** - Null Hypothesis (\(H_0\)): \(\mu = 2.32\) (not claim) - Alternative Hypothesis (\(H_1\)): \(\mu \neq 2.32\) (claim) This test is a two-tailed test. **Determine the P-value:** P-value = _______ **Decision Rule:** Based on the calculated P-value, decide whether to reject the null hypothesis (\(H_0\)). **Question: Reject Null Hypothesis or not?** Analyze the results based on the significance level \(\alpha = 0.01\).
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