Catalogue data for R-134A compressor with a displacement of 75 L/s show the capacity to be 8 tons when the suction conditions are 0.1 MPa and -20°C and condensing temperature is 50°C. The refrigerant leaves the condenser as saturated liquid. Calculate the actual volumetric efficiency and the brake work of the compressor if the compressor efficiency is,70%.
Catalogue data for R-134A compressor with a displacement of 75 L/s show the capacity to be 8 tons when the suction conditions are 0.1 MPa and -20°C and condensing temperature is 50°C. The refrigerant leaves the condenser as saturated liquid. Calculate the actual volumetric efficiency and the brake work of the compressor if the compressor efficiency is,70%.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
100%
![20
4)
1300-
T=-40°C
-30 1400
-20
1350
OL-
2.
09-
1250
1200
1150 <-
-50 1450
1100
09
08
06
00,
PRESSURE, MPa
006 2
కికి కి
work of the compressor if the compressor efficiency is,70%.
as saturated liquid. Calculate the actual volumetric efficiency and the brake
pinbn pejemes
2,
0.1.
and condensing temperature is 50°C. The refrigerant leaves the cond
the capacity to be 8 tons when the suction conditions are 0.1 MPa and -20°C
20
0.70
F0 = x
Catalogue data for R-134A compressor with a displacement of 75 L/s show
0.3
10
0.80:
-06'0
Problem:
- 00'L
CO
0.5
0.6-
4,
1.10 -
PLEASE..
the full solution of this problem and needs it to be clear solution
needed). I need to see the enthalpy graph in the chart below. I need
8-1.30 -
1.40
1.20
0.7
0.8-
2.
0.9-
Instruction: I want the t-s diagram , p-v diagram and (schematic if
Saturated Vapor
09
08
06
1.60-
100
110
1.70 -
1.80
T = 160°C
+170 -
180
06
140
150
= 2.30 kJ/(kg-K)
enser
001
350
R-134a
00s
(1,1,1,2-totrafluoroethane)
Reference state:
h= 200.0 kJ/kg. s=1.00 kJ/(kg-K)
for saturated liquid at 0°C
009
1050-
500 kg/m³
0.2
0.02
08'0
09'0
0.02
0.01
250
Properties computed with: NIST REFPROP
007
350
450
ENTHALPY, kJ/kg
0.01
00p
009
Based on formulation of Tilliner-Roth and Baehr (1994)
009](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa26fe0ca-174e-4be3-a286-632c67c61642%2F25bc412b-efe6-40f0-8f04-9a1b22b7626d%2Fq1tuo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:20
4)
1300-
T=-40°C
-30 1400
-20
1350
OL-
2.
09-
1250
1200
1150 <-
-50 1450
1100
09
08
06
00,
PRESSURE, MPa
006 2
కికి కి
work of the compressor if the compressor efficiency is,70%.
as saturated liquid. Calculate the actual volumetric efficiency and the brake
pinbn pejemes
2,
0.1.
and condensing temperature is 50°C. The refrigerant leaves the cond
the capacity to be 8 tons when the suction conditions are 0.1 MPa and -20°C
20
0.70
F0 = x
Catalogue data for R-134A compressor with a displacement of 75 L/s show
0.3
10
0.80:
-06'0
Problem:
- 00'L
CO
0.5
0.6-
4,
1.10 -
PLEASE..
the full solution of this problem and needs it to be clear solution
needed). I need to see the enthalpy graph in the chart below. I need
8-1.30 -
1.40
1.20
0.7
0.8-
2.
0.9-
Instruction: I want the t-s diagram , p-v diagram and (schematic if
Saturated Vapor
09
08
06
1.60-
100
110
1.70 -
1.80
T = 160°C
+170 -
180
06
140
150
= 2.30 kJ/(kg-K)
enser
001
350
R-134a
00s
(1,1,1,2-totrafluoroethane)
Reference state:
h= 200.0 kJ/kg. s=1.00 kJ/(kg-K)
for saturated liquid at 0°C
009
1050-
500 kg/m³
0.2
0.02
08'0
09'0
0.02
0.01
250
Properties computed with: NIST REFPROP
007
350
450
ENTHALPY, kJ/kg
0.01
00p
009
Based on formulation of Tilliner-Roth and Baehr (1994)
009
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