Carbon occurs in two forms, graphite and diamond. Theenthalpy of the combustion of graphite is -393.5 kJ/moland that of diamond is -395.4 kJ/mol:C (graphite) + O2 (g) → CO2 (g)C (diamond) + 02 (g)AH1 = -393.5 kJCO2 (g)AH2 = -395.4 kJCalculate AH3 for the conversion of graphite to diamond:C (graphite)C (diamond)AH3 = ? kJ%3D

given, 1) combustion of graphite C (graphite) + O2(g) → CO2(g) , ΔH1 = -393.5 KJ -1 2)…

Carbon occurs in two forms, graphite and diamond. The enthalpy of the combustion of graphite is -393.5 kJ/mol and that of diamond is -395.4 kJ/mol: C (graphite) + O2 (g) C (diamond) + O2 (g) → CO2 (g) AH1 = -393.5 kJ CO2 (g) AH2 = -395.4 kJ Calculate AH3 for the conversion of graphite to diamond: C (graphite) C (diamond) AH3 = ? kJ

Carbon occurs in two forms, graphite and diamond. The enthalpy of the combustion of graphite is -393.5 kJ/mol and that of diamond is -395.4 kJ/mol: C (graphite) + O2 (g) C (diamond) + O2 (g) → CO2 (g) AH1 = -393.5 kJ CO2 (g) AH2 = -395.4 kJ Calculate AH3 for the conversion of graphite to diamond: C (graphite) C (diamond) AH3 = ? kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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