Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium: Hb(0₂)4(aq) + 4CO(g) Hb(CO)4(aq) + 40₂(g) From Le Châtelier's principle, CO poisoning is reversed by A) increasing the O₂ pressure. B) decreasing the amount of Hb. C) increasing the CO2 pressure. D) increasing the CO pressure. E) increasing the amount of Hb.
Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium: Hb(0₂)4(aq) + 4CO(g) Hb(CO)4(aq) + 40₂(g) From Le Châtelier's principle, CO poisoning is reversed by A) increasing the O₂ pressure. B) decreasing the amount of Hb. C) increasing the CO2 pressure. D) increasing the CO pressure. E) increasing the amount of Hb.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Oo.168.
Subject:- Chemistry
![Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb)
sites according to the following equilibrium:
Hb(0₂)4(aq) + 4CO(g)
Hb(CO)4(aq) + 402(g)
From Le Châtelier's principle, CO poisoning is reversed by
A) increasing the O2 pressure.
C)
B) decreasing the amount of Hb.
increasing the CO2 pressure.
D) increasing the CO pressure.
E) increasing the amount of Hb.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a79f5fd-2bdd-484b-9c0d-a83d48b55247%2Fedec508e-98d2-4652-8fbc-35a07abd5d85%2Fwglfbww_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb)
sites according to the following equilibrium:
Hb(0₂)4(aq) + 4CO(g)
Hb(CO)4(aq) + 402(g)
From Le Châtelier's principle, CO poisoning is reversed by
A) increasing the O2 pressure.
C)
B) decreasing the amount of Hb.
increasing the CO2 pressure.
D) increasing the CO pressure.
E) increasing the amount of Hb.
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