Carbon monoxide and the cyanide ion are both toxic because they bind more strongly than Oxygen to the iron in hemoglobin (Hb) complex. I ma Given the following equations: Hb + O2 HbO2 Keg - 2.0 x 1012 %3! Hb + CO ==== HBCO Keg - 1.0 x 1014 where --=- is the "double arrow" a) Write the balanced equation for the ligand exchange of O, by CO. Calculate the equilibrium constant. b) Does the equilibrium favor reactants or products? Calculate the Standard Free Energy for the exchange.

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Carbon monoxide and the cyanide ion are both toxic because they bind more strongly than Oxygen
to the iron in hemoglobin (Hb) complex.
Given the following equations:
Hb + O2
HbO2
Keg = 2.0 x 1012
!3!
Hb + CO ==== HBCO
Kea
= 1.0 x 1014
where ===m is the "double arrow"
a) Write the balanced equation for the ligand exchange of Oz by CO.
Calculate the equilibrium constant.
b) Does the equilibrium favor reactants or products?
Calculate the Standard Free Energy for the exchange.
Transcribed Image Text:Carbon monoxide and the cyanide ion are both toxic because they bind more strongly than Oxygen to the iron in hemoglobin (Hb) complex. Given the following equations: Hb + O2 HbO2 Keg = 2.0 x 1012 !3! Hb + CO ==== HBCO Kea = 1.0 x 1014 where ===m is the "double arrow" a) Write the balanced equation for the ligand exchange of Oz by CO. Calculate the equilibrium constant. b) Does the equilibrium favor reactants or products? Calculate the Standard Free Energy for the exchange.
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