Car A is traveling twice as fast as car B, with v4-2vB Both cars begin braking at the same time with the same acceleration a. The relationship between the distance dA traveled by car A before stopping and the distance dg traveled by car B before stopping is: da = dg da = 2dg da = 4dB da = v2dB

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Chapter1: Units, Trigonometry. And Vectors
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Car A is traveling twice as fast as car B, with va-2vg Both cars begin braking at the
same time with the same acceleration a. The relationship between the distance dA
traveled by car A before stopping and the distance dg traveled by car B before
stopping is:
da = de
da = 2dB
da = 4dB
da = v2dB
Transcribed Image Text:Car A is traveling twice as fast as car B, with va-2vg Both cars begin braking at the same time with the same acceleration a. The relationship between the distance dA traveled by car A before stopping and the distance dg traveled by car B before stopping is: da = de da = 2dB da = 4dB da = v2dB
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