cannon uses a spring to project a 5.30-g soft rubber ball. The spring is originally compressed by 5.00 cm and has a force constant of 8.00 N/m. When the cannon is fired, the ball moves 15.0cm through the horizontal barrel of the cannon and the barrel exerts a constant friction force of 0.0320N on the ball. (a) With what speed does the projectile leave the barrel of the cannon? (b) At what point does the ball have maximum speed? (c) What is this

Q: A 6.00-kg object is attached to one end of a horizontal spring that has a negligible mass and a…

A: Given Mass of object = 6.0 kg Spring constant = 300 N/m Compression in spring given = 10 cm from the…

Q: A toy gun uses a spring to project a 5.0-g soft rubber sphere horizontally. The spring constant is…

A: Given data : Projectile's mass, Spring constant, Barrel's length, Frictional force constant,…

Q: A toy cannon uses a spring to project a 5.28 -g soft rubber ball. The spr a force constant of 8.04…

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Q: A vertically mounted spring (k = 850 N/m) is compressed by 24.0 cm relative to its unstrained…

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Q: 61.When a 3.0-kg block is pushed against a massless spring of force constant constant 4.5×10' N/m,…

A: To determine: The coefficient of kinetic friction between the block and the surface Given: Force…

Q: The figure to the right shows a pool slide of length 5.50 m. The end point of the slide is at 30.0…

A: Length of pool slide = 5.50 m height of end point of slide above water level = 30 cm mass of child =…

Q: A 5.50 ✕ 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.800 m by a large…

A: The kinetic energy of the train can be obtained as KE=12mv2=125.50×105kg0.500m/s2=68750J

Q: A weight of 40N is placed on a horizontal plane touching one end of a horizontal spring whose other…

A: Given spring constant k= 5N/mm=5000N/m Weight of block =40N this gives mass m of block =4.08kg ~4 kg…

Q: by strings to a vertical, rotating rod. The strings a e upper string is 24.0 cm long and has a…

A: Centripetal force = mv2 /r

Q: A particular spring has a rest length of 5.0 cm when it is not compressed, and a length of 4.5 cm…

A: Given data: The free length of spring is l=5 cm. Length with m=10 kg l'=4.5 cm. Acceleration of…

Q: Pi- Pf 1. (m, + m,) VBw= m,VB VWB =mg V (mB + m,) nce combined, the bullet+block system swing upward…

A: (1) Given: The mass of the bullet is mB. The mass of the block is mw. The initial velocity of bullet…

Q: A spring that has a force constant of 1050 N/m is mounted vertically on the ground. A block of mass…

A: Given that:- Spring constant=K=1050N

Q: A 189 g block is launched by compressing a spring of constant k =200N/m a distance of 15 cm. The…

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Q: A 2.0 kg block is pushed against a horizontal spring compressing the spring by 15 cm.  When the…

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Q: A 3.0 kg block falling from a height of 7.0 m landed on a vertical spring whose force constant is 2…

A: Given in question:  Mass of block (M) = 3.0 kg                                  Height of block (H)…

Q: In the figure, a block of mass m = 3.30 kg slides from rest a distance d down a frictionless incline…

A: Mass (m) = 3.3kg   θ = 35.0 ˚ ( Angle of inclination)   Spring constant (k)= 450N/m  Compression (x)…

Q: A 6.50 ✕ 105 kg subway train is brought to a stop from a speed of 0.600 m/s in 0.800 m by a large…

A: According to question---- Given data--- Mass m = 6.5 × 105 kg. Speed = 0.6 m / sec. X = 0.8 m. We…

Q: A net force along the x-axis that has x-component Fx=−12.0N+(0.300N/m^2)x^2 is applied to a 3.80 kg…

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Q: A constant net force of 60.0 N acts on an object initially at rest and acts through a parallel…

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Q: The 1.1 kgkg physics book in figure is connected by a string to a 550 gg coffee cup. The book is…

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Q: A 200-g steel ball is tied to a 2.00-m “massless” string and hung from the ceiling to make a…

A: We draw a diagram according to the question. Also take  dotted line below the figure as a reference…

Q: A toy gun uses a spring to project a 6.0-g soft rubber sphere horizontally. The spring constant is…

A: Given:The mass of the sphere is 6 g. The spring constant is 8 N/m. The total length of the barrel is…

Q: A) A1.2 kg block slides down a frictionless incline with a slope angle of 42°, starting from a…

A: Calculate the potential energy, PE, of the block at height h from the incline's bottom. PE=mgh=1.2…

Q: A toy cannon uses a spring to project a 5.35-g soft rubber ball. The spring is originally compressed…

A: Given that, m =5.35 g =5.35 x 10-3 kg x =4.96 cm =0.05 m k =8.02 N/m d =15.8 cm =0.16 m fk =0.0319 N

Q: It's your birthday, and you decide to celebrate by bungee-jumping. You stand on a bridge 100 m above…

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Q: 10. A vertically mounted spring (k = 750 N/m) is compressed by 30.0 cm relative to its unstrained…

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Q: The launching mechanism of a toy gun consists of a spring of unknown spring constant, as shown in…

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Q: A spring that has a force constant of 1150 N/m is mounted vertically on the ground. A block of mass…

A: Given data-               spring constant (K) = 1150 N/m               block mass (m) = 1.35 Kg…

Q: A ball with mass of 300 g is held on top of a vertical spring that has been compressed by 10 cm. The…

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Q: A net force along the x-axis that has x-component Fx = −12.0N + (0.300N/m2)x2 is applied to a 5.00…

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Q: A warehouse worker is pushing a 90.0 kg crate with a horizontal force of 291 N at a speed of v =…

A:

Q: In a pinball machine, a horizontal spring with a spring constant of 31 N/m, is compressed by 4.0 cm…

A: Now since there is no loss of energy. The potential energy of the compressed spring will be equal to…

Q: A 3.00 kgkg mass is pushed against a horizontal spring of force constant 28.0 N/cmN/cm on a…

A: Given, Mass of block ( m)= 3kg  Spring constant (k)= 28 N/cm = 2800 N/m Mass is released from rest…

Q: Consider a block of mass 0.220 kg attached to a spring of spring constant 120 N/m. The block is…

A: m = 0.220 kg K = 120 N/m x1 = 11.2 cm = 0.112 m

Q: A block of mass 0.5 kg is initially resting against the spring, compressing the spring at a distance…

A: mass of block (m) = 0.5 kg spring constant (k) = 400 Nmcompression in the spring (∆x) = 15 cm = 0.15…

Q: a mother and her child are skiing together, and the mother is holding the end of a rope tied to the…

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Q: spring with a constant of 50.0 N/cm. The launcher is prepared by compressing the spring by 5.00 cm.…

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Q: A toy gun uses a spring to project a 5.2-g soft rubber sphere horizontally. The spring constant is…

A:

Q: A block of mass m = 3.08 kg is attached to a spring that is resting on a horizontal, frictionless…

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Q: The spring force is initially greater than friction, so the block accelerates forward. But…

A: Given : Xo=0.400m, m =0.300kg  v²(t) =?

Q: the figure, a block weighing 16.1 N, which can slide without friction on an incline at angle e =…

A: Given values:- Block weight,(W)=16.1 N ---(1) Angle,(θ)=50 0 ----(2) Unstretched length,(l)=0.550 m…

Q: A slingshot, which can be modeled as a spring with spring constant k = 56.4 N/m, is stretched by 16…

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.