candidate A is facing two opposing candidates. In a preselected poll of 100 residents supported candidate B and 14 supported candidate C. Can we conclude that more than 60% of residents population supported candidate A? Conduct the test with a = 0.05 Which of the following statements is (are) correct? This is a multiple-answer question. It may have more t correct answers. Di. The proportion of residents supported candidate A based on this sample is (100-22-14)/100-0.64. ii. The null hypothesis is p > 0.6 and the alternative hypothesis is p = 0.6
candidate A is facing two opposing candidates. In a preselected poll of 100 residents supported candidate B and 14 supported candidate C. Can we conclude that more than 60% of residents population supported candidate A? Conduct the test with a = 0.05 Which of the following statements is (are) correct? This is a multiple-answer question. It may have more t correct answers. Di. The proportion of residents supported candidate A based on this sample is (100-22-14)/100-0.64. ii. The null hypothesis is p > 0.6 and the alternative hypothesis is p = 0.6
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:In a mayoral election, candidate A is facing two opposing candidates. In a preselected poll of 100 residents, 22
supported candidate B and 14 supported candidate C. Can we conclude that more than 60% of residents in the
population supported candidate A? Conduct the test with,
a = 0.05.
Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one
correct answers.
Oi. The proportion of residents supported candidate A based on this sample is (100-22-14)/100-0.64.
O ii. The null hypothesis is p > 0.6 and the alternative hypothesis is p = 0.6
P
iii. The rejection region is (1.645, infinity).
iv. The resulting statistic is z' =
0.64-0.6
04104
100
= 0.82. The p-value is p(z > 0.82) = 1-0.7939 = 0.2061.
□v. Since 0.2061 > 0.05, we reject the null hypothesis. We conclude that the population proportion is greater than 0.6.
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