A company maintains three offices in a certain region, each staffed by two employees. Information concerning yearly salaries (1000s of dollars) is as follows: Office 1 1 2 2 3 3 T Employee 1 2 3 4 5 6 30.2 Salary 29.7 33.6 (a) Suppose two of these employees are randomly selected from among the six (without replacement). Determine the sampling distribution of the sample mean salary X. (Enter your answers for p(x) as fractions.) 27.75 P(x) 33.6 25.8 29.7 p(x) 15 29.70 29.95 31.65 15 (b) Suppose one of the three offices is randomly selected. Let X₁ and X₂ denote the salaries of the two employees. Determine the sampling distribution of X. (Enter your answers as fractions.) 27.75 31.65 31.90 33.60 (c) How does E(X) from parts (a) and (b) compare to the population mean salary μ? E(X) from part (a) is ---Select---μ, and E(X) from part (b) is ---Select---

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 5E: List the sample space of each experiment. Rolling one die and tossing one coin
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A company maintains three offices in a certain region, each staffed by two employees. Information
concerning yearly salaries (1000s of dollars) is as follows:
Office
1
1
2
2
3
Employee 1
2
3
4
5
Salary 29.7 33.6 30.2 33.6 25.8
P(x)
(a) Suppose two of these employees are randomly selected from among the six (without
replacement). Determine the sampling distribution of the sample mean salary X. (Enter your
answers for p(x) as fractions.)
27.75
x
p(x)
15
3
6
29.7
29.70
29.95
31.65
31.65
2
15
(b) Suppose one of the three offices is randomly selected. Let X₁ and X₂ denote the salaries of
the two employees. Determine the sampling distribution of X. (Enter your answers as fractions.)
27.75
31.90
33.60
(c) How does E(X) from parts (a) and (b) compare to the population mean salary μ?
E(X) from part (a) is ---Select---μ, and E(X) from part (b) is ---Select---
✓H.
Transcribed Image Text:A company maintains three offices in a certain region, each staffed by two employees. Information concerning yearly salaries (1000s of dollars) is as follows: Office 1 1 2 2 3 Employee 1 2 3 4 5 Salary 29.7 33.6 30.2 33.6 25.8 P(x) (a) Suppose two of these employees are randomly selected from among the six (without replacement). Determine the sampling distribution of the sample mean salary X. (Enter your answers for p(x) as fractions.) 27.75 x p(x) 15 3 6 29.7 29.70 29.95 31.65 31.65 2 15 (b) Suppose one of the three offices is randomly selected. Let X₁ and X₂ denote the salaries of the two employees. Determine the sampling distribution of X. (Enter your answers as fractions.) 27.75 31.90 33.60 (c) How does E(X) from parts (a) and (b) compare to the population mean salary μ? E(X) from part (a) is ---Select---μ, and E(X) from part (b) is ---Select--- ✓H.
When an automobile is stopped by a roving safety patrol, each tire is checked for tire wear, and each
headlight is checked to see whether it is properly aimed. Let X denote the number of headlights that
need adjustment, and let y denote the number of defective tires.
(a) If X and Y are independent with px(0) 0.5, px(1) = 0.3, px(2) = 0.2, and py(0) = 0.2,
Py(1) = 0.1, py(2) = py(3) = 0.05, py(4) = 0.6, display the joint pmf of (X, Y) in a joint
probability table.
p(x, y)
0
1
0
No
1
=
у
2
(b) Compute P(X ≤ 1 and Y≤ 1) from the joint probability table.
P(X ≤ 1 and Y ≤ 1)
(d) Compute P(X + Y ≤ 1).
P(X + Y ≤ 1) =
Does P(X ≤ 1 and Y ≤ 1) equal the product P(X ≤ 1). P(Y ≤ 1)?
O Yes
3
(c) What is P(X + Y = 0) (the probability of no violations)?
P(X + Y = 0) =
4
Transcribed Image Text:When an automobile is stopped by a roving safety patrol, each tire is checked for tire wear, and each headlight is checked to see whether it is properly aimed. Let X denote the number of headlights that need adjustment, and let y denote the number of defective tires. (a) If X and Y are independent with px(0) 0.5, px(1) = 0.3, px(2) = 0.2, and py(0) = 0.2, Py(1) = 0.1, py(2) = py(3) = 0.05, py(4) = 0.6, display the joint pmf of (X, Y) in a joint probability table. p(x, y) 0 1 0 No 1 = у 2 (b) Compute P(X ≤ 1 and Y≤ 1) from the joint probability table. P(X ≤ 1 and Y ≤ 1) (d) Compute P(X + Y ≤ 1). P(X + Y ≤ 1) = Does P(X ≤ 1 and Y ≤ 1) equal the product P(X ≤ 1). P(Y ≤ 1)? O Yes 3 (c) What is P(X + Y = 0) (the probability of no violations)? P(X + Y = 0) = 4
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