can you please provide an explanation for the answer ? 11. If the double crossover event depicted below occurs during meiosis, which sets of gametes could be produced at the indicated frequencies? B IC 16 16 A) ABC 30% and abc = 15% B) abc 15% and aBC = 30% C) AbC = 30% and aBc 10% D) ABC = 30% and AbC = 5% E) aBc = 5% and ABc 40% CLinnamatee underan nondisiunction of the sex

can you please provide an explanation for the answer ? 11. If the double crossover event depicted below occurs during meiosis, which sets of gametes could be produced at the indicated frequencies? B IC 16 16 A) ABC 30% and abc = 15% B) abc 15% and aBC = 30% C) AbC = 30% and aBc 10% D) ABC = 30% and AbC = 5% E) aBc = 5% and ABc 40% CLinnamatee underan nondisiunction of the sex

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 17RQ: Assuming no gene linkage, in a dihybrid cross of AABB x aabb with AaBb F1 heterozygotes, what is the...

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a) Explain why when a chiasma is formed, only 50% of the meiotic products will be of recombinant type. b) Determine the sequence of the three genes (y, cl and vg) that are linked on a chromosome based on the genetic distances provided below: y- vg 43 y- cl vg – cl 5 38
In com, male sterility is controlled by maternal cytoplasmic elements. However, the presence of a nuclear fertility restorer gene (F_) restores fertility to male sterile lines. a. What are the crosses male sterile female x FF male? Give the genotypes and phenotypes of the offspring in each cross. Explain.
Is )Given the experimental set up below, and knowing the genes for stalked eyes (st) and black bodies (b) are on the same chromosome and recessive to wild type (un-stalked eyes and light body), answer the questions below the diagram. 1. st st F1 F2 A = 489 B = 56 C= 497 D= 49 A) ) How many recombinant animals are in the F2 generation? B) woH) How far apart, (as both a % recombination and in map units) are the stalk eyed and black bodied genes on this chromosome?
Females heterozygous for the recessive second chromosome mutations px, sp, and cn are mated to a male homozygous for all three mutations. The offspring are as follows: Must show all work 1.) What gene is in the middle? and what are the map distances between the genes in centimorgans? 2.) What is the interference?
Please answer all parts along with the reason. I'll definitely give a like. Thank you in advance! 1A) From the cross Ab/aB x ab/ab, what is the recombination frequency if the progeny numbers are 17 AB/ab, 72 Ab/ab, 68 aB/ab, and 21 ab/ab? 1B)In human gene mapping, a LOD score is calculated to see if a gene causing a rare disease is linked to a known SNP. The LOD score is -4. This means that 1C) A three-point testcross is used to determine the order of three linked genes. The following crossover progeny result: single crossovers, double crossovers, and no crossovers. To determine the order, the no-crossover progeny must be compared to what other class of progeny?
n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines sing the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspring
Explain the following: a- No parental type is produced during gametogenesis? b- A dominant wild type produced a sign spot in Drosophila? c- 9:7 phenotypic ratio is produced in dihybrid cross? d- 50% parental type gametes were produced during gametogenesis? e- All recombinant gametes were produced during gametogenesis?
Assignment 1 A pure strain of Mendel's peas, dominant for all seven of his independently assorting genes, was testcrossed. a) How many different kinds of gametes could each of the parents produce? b) How many different gametes could the F, produce? Assignments Assignment 1 c) If the F, was testcrossed, how many phenotypes would be expected in the offspring and in what proportion? d) How many genotypes would be expected in the F,?
7. Complete the following problem. Assume that a diploid cell heterozygous for the MET15/met1540; LYS2/lys240, and MatA/Mata (i.e. the BY4743 strain) was sporulated. For one tetrad, you obtained the following results. a. Assuming only independent assortment, draw out the one independent assortment that led to this result. tetrad YPD SD-met SD-lys mating type tester 1a + + 1b + + - 1c + + + 1d + + + b. Use the branch method to identify all possible gamete genotypes that could have arisen from diploid strain.
Assuming no gene linkage, in a dihybrid cross of AABB x aabb with AaBb F1 heterozygotes, what is the ratio of the F1 gametes (AB, aB, Ab, ab) that will give rise to the F2 offspring? a. 1:1:1:1 b. 1:3:3:1 c. 1:2:2:1 d. 4:3:3:1
6). To investigate the genetic control of locomotive behavior in the diploid nematode, Caenorhabditis elegans, eight "wiggly" mutants were isolated, which wiggle in an uncoordinated way rather than smoothly gliding. These eight mutants were crossed together in all possible pairwise combinations, yielding the results summarized in the table above (+ means that all the progeny were wild type, and m means that all the progeny showed the wiggly mutant phenotype). Organize the eight mutations into con lementation groups, each consisting of a group of mutations affecting the same gene. 1 2 3 4 5 6 7 8 1 E N+E 2 3+1 m + m 4 5 + m m E+ + + EE 6 ++E E+ +EE m m + + + + + + + + + m 7 8 ++4 ∞+E +E m m ++ E