Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you please help identify the hybridization state?

Transcribed Image Text:**Title:** Identifying Hybridization States of Indicated Atoms
**Objective:** Determine the hybridization states of the specified atoms in the given molecular structure.
**Description:**
Below is a molecular structure with three atoms labeled I, II, and III. Your task is to identify the hybridization states of these atoms.
**Molecular Structure and Indicated Atoms:**
- Atom I is part of a nitro group (NO2) attached to a benzene ring.
- Atom II is an oxygen atom double-bonded to a carbon atom.
- Atom III is a carbon atom connected to another carbon atom, which is part of an ethyl side chain.
**Options Provided:**
1. (I) sp³; (II) sp³; (III) sp³
2. (I) sp²; (II) sp³; (III) sp
3. (I) sp³; (II) sp²; (III) sp
4. (I) sp²; (II) sp²; (III) sp³
**Diagram Explanation:**
The diagram depicts the molecular structure with arrows pointing to the atoms in question:
- **Atom I**: Attached to the nitrogen of the nitro group (NO2).
- **Atom II**: The oxygen atom double-bonded to a carbon atom (part of a carbonyl group).
- **Atom III**: The carbon atom in the ethyl side chain.
**Answer Key Discussion:**
The hybridization of each atom can be deduced as follows:
- **Atom I (Nitrogen in NO2 group):** Typically, nitrogen in a nitro group (NO2) adopts sp² hybridization.
- **Atom II (Oxygen in carbonyl group):** Oxygen in a carbonyl group (C=O) is sp² hybridized due to its double-bonded nature.
- **Atom III (Carbon in ethyl side chain):** Carbon in an alkyl chain (C-C) has sp³ hybridization if it forms three single bonds and one bond with a hydrogen atom.
Based on these rules, the correct hybridization states for the atoms are:
**(I) sp²; (II) sp²; (III) sp³**
**Correct Option:**
4. (I) sp²; (II) sp²; (III) sp³
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