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can you find out the 3 decimal places in final answer of A and B?

can you find out the 3 decimal places in final answer of A and B?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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can you find out the 3 decimal places in final answer of A and B? thank you
14:08 A brainly.com BRAINLY Search... Answer: a) The additional time required for the truck to stop is 8.5 seconds b) The additional distance traveled by the truck is 230.05 ft Explanation: Since the acceleration is constant, the average speed is: (final speed - initial speed) / 2 = 0.75 v0 Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for vo: 0.75v0 * 8.5 = 690 vO = 108.24 ft/s The speed after 8.5 seconds is: 108.24 /2 = 54.12 ft/s We can now use the following equation to solve for acceleration: v2 – u? = 2 * a * s 54.122 – 108.24² = 2 * a * 690 a = -6.367 m/s^2 Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds Total distance traveled: v² – u² = 2 * a * s 0 - 108 24^2 = 2-6 36 S
Transcribed Image Text:14:08 A brainly.com BRAINLY Search... Answer: a) The additional time required for the truck to stop is 8.5 seconds b) The additional distance traveled by the truck is 230.05 ft Explanation: Since the acceleration is constant, the average speed is: (final speed - initial speed) / 2 = 0.75 v0 Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for vo: 0.75v0 * 8.5 = 690 vO = 108.24 ft/s The speed after 8.5 seconds is: 108.24 /2 = 54.12 ft/s We can now use the following equation to solve for acceleration: v2 – u? = 2 * a * s 54.122 – 108.24² = 2 * a * 690 a = -6.367 m/s^2 Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds Total distance traveled: v² – u² = 2 * a * s 0 - 108 24^2 = 2-6 36 S
14:08 A brainly.com BRAINLY Search... speed is: (final speed - initial speed) / 2 = 0.75 v0 Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for vo: 0.75v0 * 8.5 = 690 vO = 108.24 ft/s The speed after 8.5 seconds is: 108.24 / 2 = 54.12 ft/s We can now use the following equation to solve for acceleration: v² – u? = 2 * a * s 54.122 – 108.24² = 2 * a * 690 a = -6.367 m/s^2 Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds Total distance traveled: v2 – u? = 2 * a * s O - 108.24^2 = 2 * (-6.367) * s solving for s we get total distance traveled = 920.05 ft Additional Distance Traveled: 920.05 - 690 = 230.05 ft ocabanga44 and 1 more users found this answer helpful
Transcribed Image Text:14:08 A brainly.com BRAINLY Search... speed is: (final speed - initial speed) / 2 = 0.75 v0 Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for vo: 0.75v0 * 8.5 = 690 vO = 108.24 ft/s The speed after 8.5 seconds is: 108.24 / 2 = 54.12 ft/s We can now use the following equation to solve for acceleration: v² – u? = 2 * a * s 54.122 – 108.24² = 2 * a * 690 a = -6.367 m/s^2 Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds Total distance traveled: v2 – u? = 2 * a * s O - 108.24^2 = 2 * (-6.367) * s solving for s we get total distance traveled = 920.05 ft Additional Distance Traveled: 920.05 - 690 = 230.05 ft ocabanga44 and 1 more users found this answer helpful
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