University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter3: Motion Along A Straight Line
Section: Chapter Questions
Problem 82AP: Professional baseball player Nolan Ryan could pitch a baseball at approximately 160.0 km/h. At that...
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Question
can you find out the 3 decimal places in final answer of A and B? thank you
![14:08
A brainly.com
BRAINLY
Search...
Answer:
a) The additional time required for the truck to
stop is 8.5 seconds
b) The additional distance traveled by the
truck is 230.05 ft
Explanation:
Since the acceleration is constant, the average
speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds
causes the vehicle to travel 690 ft, we can solve
for vo:
0.75v0 * 8.5 = 690
vO = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 /2 =
54.12 ft/s
We can now use the following equation to solve
for acceleration:
v2 – u? = 2 * a * s
54.122 – 108.24² = 2 * a * 690
a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367
= 8.5 seconds
Total distance traveled:
v² – u² = 2 * a * s
0 - 108 24^2 = 2-6 36 S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6330c436-2231-44d0-a3e2-25fec5d08ab5%2F93c4ddd9-e595-41e3-9ed2-fdc7b25c8f97%2Fyacioqp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:14:08
A brainly.com
BRAINLY
Search...
Answer:
a) The additional time required for the truck to
stop is 8.5 seconds
b) The additional distance traveled by the
truck is 230.05 ft
Explanation:
Since the acceleration is constant, the average
speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds
causes the vehicle to travel 690 ft, we can solve
for vo:
0.75v0 * 8.5 = 690
vO = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 /2 =
54.12 ft/s
We can now use the following equation to solve
for acceleration:
v2 – u? = 2 * a * s
54.122 – 108.24² = 2 * a * 690
a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367
= 8.5 seconds
Total distance traveled:
v² – u² = 2 * a * s
0 - 108 24^2 = 2-6 36 S
![14:08
A brainly.com
BRAINLY
Search...
speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds
causes the vehicle to travel 690 ft, we can solve
for vo:
0.75v0 * 8.5 = 690
vO = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 / 2 =
54.12 ft/s
We can now use the following equation to solve
for acceleration:
v² – u? = 2 * a * s
54.122 – 108.24² = 2 * a * 690
a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367
= 8.5 seconds
Total distance traveled:
v2 – u? = 2 * a * s
O - 108.24^2 = 2 * (-6.367) * s
solving for s we get total distance traveled =
920.05 ft
Additional Distance Traveled: 920.05 - 690 =
230.05 ft
ocabanga44 and 1 more users found this answer helpful](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6330c436-2231-44d0-a3e2-25fec5d08ab5%2F93c4ddd9-e595-41e3-9ed2-fdc7b25c8f97%2Faw0sjrng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:14:08
A brainly.com
BRAINLY
Search...
speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds
causes the vehicle to travel 690 ft, we can solve
for vo:
0.75v0 * 8.5 = 690
vO = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 / 2 =
54.12 ft/s
We can now use the following equation to solve
for acceleration:
v² – u? = 2 * a * s
54.122 – 108.24² = 2 * a * 690
a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367
= 8.5 seconds
Total distance traveled:
v2 – u? = 2 * a * s
O - 108.24^2 = 2 * (-6.367) * s
solving for s we get total distance traveled =
920.05 ft
Additional Distance Traveled: 920.05 - 690 =
230.05 ft
ocabanga44 and 1 more users found this answer helpful
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